• Mysql 练习题 及 答案


    --1.学生表
    Student(S,Sname,Sage,Ssex) --S
    学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别
    --2.
    课程表 
    Course(C,Cname,T) --C --
    课程编号,Cname 课程名称,T 教师编号
    --3.
    教师表 
    Teacher(T,Tname) --T
    教师编号,Tname 教师姓名
    --4.
    成绩表 
    SC(S,C,score) --S
    学生编号,C 课程编号,score 分数
    */

    --创建测试数据
    create table Student(Svarchar(10),Sname varchar(10),Sage datetime,Ssex nvarchar(10))

    insert into Student values('01' , '赵雷' , '1990-01-01' , '')
    insert into Student values('02' , '
    钱电' , '1990-12-21' , '')
    insert into Student values('03' , '
    孙风' , '1990-05-20' , '')
    insert into Student values('04' , '
    李云' , '1990-08-06' , '')
    insert into Student values('05' , '
    周梅' , '1991-12-01' , '')
    insert into Student values('06' , '
    吴兰' , '1992-03-01' , '')
    insert into Student values('07' , '
    郑竹' , '1989-07-01' , '')
    insert into Student values('08' , '
    王菊' , '1990-01-20' , '')
    create table Course(Cvarchar(10),Cname,varchar(10),T varchar(10))

    insert into Course values('01' , '语文' , '02')
    insert into Course values('02' , '
    数学' , '01')
    insert into Course values('03' , '
    英语' , '03')
    create table Teacher(T varchar(10),Tname,varchar(10))

    insert into Teacher values('01' , '张三')
    insert into Teacher values('02' , '
    李四')
    insert into Teacher values('03' , '
    王五')
    create table SC(S varchar(10),Cvarchar(10),score decimal(18,1))

    insert into SC values('01' , '01' , 80)
    insert into SC values('01' , '02' , 90)
    insert into SC values('01' , '03' , 99)
    insert into SC values('02' , '01' , 70)
    insert into SC values('02' , '02' , 60)
    insert into SC values('02' , '03' , 80)
    insert into SC values('03' , '01' , 80)
    insert into SC values('03' , '02' , 80)
    insert into SC values('03' , '03' , 80)
    insert into SC values('04' , '01' , 50)
    insert into SC values('04' , '02' , 30)
    insert into SC values('04' , '03' , 20)
    insert into SC values('05' , '01' , 76)
    insert into SC values('05' , '02' , 87)
    insert into SC values('06' , '01' , 31)
    insert into SC values('06' , '03' , 34)
    insert into SC values('07' , '02' , 89)
    insert into SC values('07' , '03' , 98)

    mysql...
    --1
    、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

    SELECT a.*,b.score AS'01分数',c.scoreAS '02分数'

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s AND b.c='01'

    INNER JOIN sc c

    ON a.s=c.s AND c.c='02'

    WHERE b.score>c.score
    --2
    、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
    --3
    、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

    SELECT a.s

           ,a.sname

           ,AVG(b.score) AS avgnum

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    GROUP BY a.s

           ,a.sname

    HAVING AVG(b.score)>60
    --4
    、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
    --5
    、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

    SELECT a.s

           ,a.sname

           ,COUNT(b.c)

           ,SUM(b.score)

    FROM student a

    LEFT JOIN sc b

    ON a.s=b.s

    GROUP BY 1,2
    --6
    、查询""姓老师的数量 

    SELECT COUNT(1) FROM teacherWHERE tname LIKE '%'
    --7
    、查询学过"张三"老师授课的同学的信息 

    SELECT a.*

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    INNER JOIN course c

    ON b.c=c.c

    INNER JOIN teacher d

    ON c.t=d.t

    WHERE d.tname='张三'

    GROUP BY 1,2,3,4

    --方法2

    SELECT a.*

    FROM student a

    LEFT JOIN (

           SELECT a.*

           FROM student a

           INNER JOIN sc b

           ON a.s=b.s

           INNER JOIN course c

           ON b.c=c.c

           INNER JOIN teacher d

           ON c.t=d.t

           WHERE d.tname='张三'

           GROUP BY 1,2,3,4

    )b

    ON a.s=b.s

    WHERE b.s IS NULL


    --8
    、查询没学过"张三"老师授课的同学的信息 

    SELECT a.*

    FROM student a

    LEFT JOIN sc b

    ON a.s=b.s

    WHERE NOT EXISTS(

                  SELECT *

                  FROM course aa

                  INNER JOIN teacher b

                  ON aa.t=b.t

                  INNER JOIN sc c

                  ON aa.c=c.c

                  WHERE b.tname='张三'

                  AND c.s=a.s

           )

    GROUP BY 1,2,3,4
    --9
    、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

    SELECT a.*

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s AND b.c='01'

    INNER JOIN sc c

    ON a.s=c.s AND c.c='02'
    --10
    、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

    select *

    from student a

    left join sc b

    on a.s=b.s and b.c='01'

    left join sc c

    on a.s=c.s and c.c='02'

    where b.c='01' and c.c is null
    --11
    、查询没有学全所有课程的同学的信息 

    SELECT a.*

    FROM student a

    LEFT JOIN sc b

    ON a.s=b.s

    LEFT JOIN (SELECT COUNT(1) anumFROM course) c

    ON 1=1

    GROUP BY 1,2,3,4

    HAVING MAX(c.anum)>COUNT(b.c)
    --12
    、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 

    SELECT a.*

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    WHERE EXISTS(

        SELECT 1 FROM sc WHERE s='01' AND c=b.c

    )

    GROUP BY 1,2,3,4
    --13
    、查询和"01"号的同学学习的课程完全相同的其他同学的信息 

    SELECTa.s,a.sname,a.sage,a.ssex

    FROM (SELECT a.*,COUNT(b.c) ASsnum

           FROM student a

           INNER JOIN sc b

           ON a.s=b.s

           WHERE EXISTS(

               SELECT 1 FROM scWHERE s='01' AND c=b.c

           )

           GROUP BY 1,2,3,4)a

    INNER JOIN (SELECTa.*,COUNT(b.c) AS anum

           FROM student a

           INNER JOIN sc b

           ON a.s=b.s

           GROUP BY 1,2,3,4)b

    ON a.s=b.s

    INNER JOIN (SELECT COUNT(1) ASnum1 FROM sc WHERE s='01')c

    ON 1=1

    WHERE a.snum=b.anum ANDa.snum=c.num1

    --方法二

     

     

    SELECT a.*

           ,COUNT(b.c) AS anum

           ,SUM(CASE WHEN EXISTS(SELECT 1 FROM sc WHERE s='01' AND c=b.c)THEN 1 ELSE 0 END) AS snum

           ,MAX(c.num1) AS num1

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    INNER JOIN (SELECT COUNT(1) ASnum1 FROM sc WHERE s='01')c

    ON 1=1

    GROUP BY 1,2,3,4

    HAVING anum=snum AND anum=num1
    --14
    、查询没学过"张三"老师讲授的任一门课程的学生姓名 

    SELECT a.*

    FROM student a

    LEFT JOIN(

           SELECT a.s

           FROM student a

           LEFT JOIN sc b

           ON a.s=b.s

           LEFT JOIN course c

           ON b.c=c.c

           LEFT JOIN teacher d

           ON c.t=d.t AND d.tname='张三'

           WHERE d.t IS NOT NULL

           )b

    ON a.s=b.s

    WHERE b.s IS NULL
    --15
    、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 

    SELECT a.s

           ,a.sname

           ,AVG(b.score)

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    GROUP BY 1,2

    HAVING SUM(CASE WHENb.score>=60 THEN 0 ELSE 1 END)>=2
    --16
    、检索"01"课程分数小于60,按分数降序排列的学生信息

    SELECT a.*

           ,b.score

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    WHERE

      b.c='01'

      AND b.score<60

    ORDER BY b.score DESC
    --17
    、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

    SELECT a.*

           ,SUM(CASE WHEN b.c='01' THEN b.scoreELSE 0 END) AS s01

           ,SUM(CASE WHEN b.c='02' THEN b.scoreELSE 0 END) AS s02

           ,SUM(CASE WHEN b.c='03' THEN b.score ELSE0 END) AS s03

           ,AVG(CASE WHEN b.score IS NULL THEN 0ELSE b.score END) avs

    FROM student a

    LEFT JOIN sc b

    ON a.s=b.s

    GROUP BY 1,2,3,4

    ORDER BY avs DESC
    --18
    、查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
    --
    及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

    SELECT a.c

           ,a.cname

           ,MAX(b.score)

           ,MIN(b.score)

           ,AVG(b.score)

           ,SUM(CASE WHEN b.score>=60 THEN 1ELSE 0 END)/COUNT(1)

           ,SUM(CASE WHEN b.score>=70 ANDb.score<80 THEN 1 ELSE 0 END)/COUNT(1)

           ,SUM(CASE WHEN b.score>=80 ANDb.score<90 THEN 1 ELSE 0 END)/COUNT(1)

           ,SUM(CASE WHEN b.score>=90 THEN 1ELSE 0 END)/COUNT(1)

    FROM course a

    INNER JOIN sc b

    ON a.c=b.c

    GROUP BY 1,2
    --19
    、按各科成绩进行排序,并显示排名

    SET @rn:=0;

    SELECT a.*,@rn:=@rn+1

    FROM(

        SELECT a.*,b.score

        FROM course a

        INNER JOIN sc b

        ON a.c=b.c

        WHERE a.c='01'

        ORDER BY b.c,score DESC

    )a
    --20
    、查询学生的总成绩并进行排名

    SELECT a.*

           ,COUNT(b.c)+1 asall

    FROM sc a

    LEFT JOIN sc b

    ON a.c=b.c ANDa.score<b.score

    GROUP BY 1,2,3

    ORDER BY a.c,asall
    --21
    、查询不同老师所教不同课程平均分从高到低显示 

    SELECT a.*

           ,b.cname

           ,AVG(c.score) ascore

    FROM teacher a

    INNER JOIN course b

    ON a.t=b.t

    INNER JOIN sc c

    ON b.c=c.c

    GROUP BY 1,2,3

    ORDER BY ascore DESC
    --22
    、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

    SELECT a.*,b.cname,b.score

    FROM student a

    INNER JOIN (

           SELECT a.*

                  ,c.cname

                  ,COUNT(b.c)+1 AStp

           FROM sc a

           LEFT JOIN sc b

           ON a.c=b.c AND a.score<b.score

           LEFT JOIN course c

           ON a.c=c.c

           GROUP BY 1,2,3,4

           HAVING COUNT(b.c)+1 IN(2,3)

           ORDER BY a.c,tp)b

    ON a.s=b.s
    --23
    、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比 

    SELECT a.c

           ,a.cname

           ,SUM(CASE WHEN b.score<=100 ANDb.score>85 THEN 1 ELSE 0 END) AS '[100-85]'

           ,SUM(CASE WHEN b.score<=85 ANDb.score>70 THEN 1 ELSE 0 END) AS '[85-70]'

           ,SUM(CASE WHEN b.score<=70 ANDb.score>60 THEN 1 ELSE 0 END) AS '[70-60]'

           ,SUM(CASE WHEN b.score<=60 ANDb.score>0 THEN 1 ELSE 0 END) AS '[60-0]'

          

           ,SUM(CASE WHEN b.score<=100 ANDb.score>85 THEN 1 ELSE 0 END)/COUNT(1) AS '[100-85]%'

           ,SUM(CASE WHEN b.score<=85 ANDb.score>70 THEN 1 ELSE 0 END)/COUNT(1) AS '[85-70]%'

           ,SUM(CASE WHEN b.score<=70 ANDb.score>60 THEN 1 ELSE 0 END)/COUNT(1) AS '[70-60]%'

           ,SUM(CASE WHEN b.score<=60 ANDb.score>0 THEN 1 ELSE 0 END)/COUNT(1) AS '[60-0]%'

    FROM course a

    INNER JOIN sc b

    ON a.c=b.c

    GROUP BY 1,2
    --24
    、查询学生平均成绩及其名次 

    SELECT a.*

           ,COUNT(b.s)+1

    FROM (

           SELECT a.*,AVG(CASE WHEN b.score IS NULL THEN 0 ELSE b.scoreEND) AS ascore

           FROM student a

           LEFT JOIN sc b

           ON a.s=b.s

           GROUP BY 1,2,3,4

          )a

    LEFT JOIN(

           SELECT a.*,AVG(CASE WHEN b.score IS NULL THEN 0 ELSE b.scoreEND) AS ascore

           FROM student a

           LEFT JOIN sc b

           ON a.s=b.s

           GROUP BY 1,2,3,4

          )b

    ON a.ascore<b.ascore

    GROUP BY 1,2,3,4,5
    --25
    、查询各科成绩前三名的记录

    SELECT a.*,COUNT(b.c)+1 ASascore

    FROM sc a

    LEFT JOIN sc b

    ON a.c=b.c ANDa.score<b.score

    GROUP BY 1,2,3

    HAVING ascore<=3

    ORDER BY a.c,ascore
    --26
    、查询每门课程被选修的学生数 

    SELECT a.*

           ,COUNT(b.s)

    FROM course a

    LEFT JOIN sc b

    ON a.c=b.c

    GROUP BY 1,2,3
    --27
    、查询出只有两门课程的全部学生的学号和姓名  

    SELECT a.*

           ,COUNT(b.c)

    FROM student a

    LEFT JOIN sc b

    ON a.s=b.s

    GROUP BY 1,2,3,4

    HAVING COUNT(b.c)=2
    --28
    、查询男生、女生人数 
    --29
    、查询名字中含有""字的学生信息
    --30
    、查询同名同性学生名单,并统计同名人数

     SELECT sname

           ,ssex

           ,COUNT(1)

    FROM student

    GROUP BY 1,2

    HAVING COUNT(1)>1
    --31
    、查询1990年出生的学生名单(注:Student表中Sage列的类型是datetime) 

    SELECT * FROM student WHEREYEAR(sage)=1990
    --32
    、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号

    SELECT a.*

           ,AVG(b.score) ascore

    FROM course a

    LEFT JOIN sc b

    ON a.c=b.c

    GROUP BY 1,2,3

    ORDER BYascore DESC,a.c

    --33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 

    SELECT a.*

           ,AVG(b.score) ascore

    FROM student a

    LEFT JOIN sc b

    ON a.s=b.s

    GROUP BY 1,2,3,4

    HAVING ascore>=85
    --34
    、查询课程名称为"数学",且分数低于60的学生姓名和分数 

    SELECT c.*

    FROM course a

    LEFT JOIN sc b

    ON a.c=b.c

    LEFT JOIN student c

    ON b.s=c.s

    WHERE a.cname='数学'

    AND b.score<60
    --35
    、查询所有学生的课程及分数情况; 

    SELECT *

    FROM sc a

    INNER JOIN student b

    ON a.s=b.s

    INNER JOIN course c

    ON a.c=c.c
    --36
    、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 

    SELECT b.sname

           ,c.cname

           ,a.score

    FROM sc a

    INNER JOIN student b

    ON a.s=b.s

    INNER JOIN course c

    ON a.c=c.c

    WHERE a.score>70
    --37
    、查询不及格的课程
    --38
    、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名; 

    SELECT a.*

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    WHERE b.c='01' AND b.score>80
    --39
    、求每门课程的学生人数 
    --40
    、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩

    SELECT a.*,b.score

    FROM student a

    INNER JOIN sc b

    ON a.s=b.s

    INNER JOIN(

           SELECT c.c

                  ,MAX(c.score) ASmaxscore

           FROM teacher a

           INNER JOIN course b

           ON a.t=b.t

           INNER JOIN sc c

           ON b.c=c.c

           WHERE a.tname='张三'

           GROUP BY c)c

    ON b.c=c.c ANDb.score=c.maxscore
    --41
    、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 

    SELECT a.s

           ,a.c

           ,a.score

    FROM sc a

    INNER JOIN (

           SELECT a.score

                  ,b.s

                  ,COUNT(1)

           FROM sc a

           INNER JOIN student b

           ON a.s=b.s

           GROUP BY a.score,b.s

           HAVING COUNT(1)>1

    )b

    ON a.s=b.s AND a.score=b.score

     

    方法二

    SELECT a.*

    FROM sc a

    LEFT JOIN sc b

    ON a.s=b.s AND a.score=b.scoreAND a.c<>b.c

    GROUP BY 1,2,3

    HAVING COUNT(b.s)>0
    --42
    、查询每门功成绩最好的前两名 
    --43
    、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列  

    SELECT a.c

           ,COUNT(1) AS pnum

    FROM sc a

    GROUP BY 1

    HAVING pnum>5

    ORDER BY pnum DESC,a.c
    --44
    、检索至少选修两门课程的学生学号 
    --45
    、查询选修了全部课程的学生信息 

    --46、查询各学生的年龄

    SELECT a.*,YEAR(CURDATE())-YEAR(a.sage)

    FROM student a
    --47
    、查询本周过生日的学生

    SELECT a.*

    FROM student a

    WHERECONCAT(MONTH(a.sage),DAY(a.sage))>=CONCAT(MONTH(SUBDATE(CURDATE(),WEEKDAY(CURDATE()))),DAY(SUBDATE(CURDATE(),WEEKDAY(CURDATE()))))

    AND CONCAT(MONTH(a.sage),DAY(a.sage))<=CONCAT(MONTH(SUBDATE(CURDATE(),WEEKDAY(CURDATE())-6)),DAY(SUBDATE(CURDATE(),WEEKDAY(CURDATE())-6)))


    --48
    、查询下周过生日的学生


    --49
    、查询本月过生日的学生

    SELECT a.* FROM student a WHEREMONTH(a.sage)=MONTH(CURDATE())
    --50
    、查询下月过生日的学生

    SELECT a.*FROM student a WHERE MONTH(a.sage)=MONTH(CURDATE())+1



    有些没有答案的,是因为和上面的差不多,偷个懒。。。。

  • 相关阅读:
    【CF516D】Drazil and Morning Exercise(换根DP预处理+暴力双指针)
    【CF538G】Berserk Robot(思维)
    【CF521D】Shop(贪心)
    【洛谷4827】[国家集训队] Crash 的文明世界(斯特林数+换根DP)
    斯特林数的基础性质与斯特林反演的初步入门
    【CF566C】Logistical Questions(点分治)
    【CF980D】Perfect Groups(仔细一想是道水题)
    【洛谷2597】[ZJOI2012] 灾难(支配树)
    2020CCPC长春站题解A D F H J K
    2020CCPC长春站自我反省
  • 原文地址:https://www.cnblogs.com/jpfss/p/9138796.html
Copyright © 2020-2023  润新知