• sicily 1324. Score


    Description

    There is an objective test result such as ``OOXXOXXOOO". An `O' means a correct answer of a problem and an `X' means a wrong answer. The score of each problem of this test is calculated by itself and its just previous consecutive `O's only when the answer is correct. For example, the score of the 10th problem is 3 that is obtained by itself and its two previous consecutive `O's.

    Therefore, the score of ``OOXXOXXOOO" is 10 which is calculated by ``1+2+0+0+1+0+0+1+2+3".

    You are to write a program calculating the scores of test results.

    Input

    Your program is to read from standard input. The input consists of T test cases. The number of test cases T is given in the first line of the input. Each test case starts with a line containing a string composed by `O' and `X' and the length of the string is more than 0 and less than 80. There is no spaces between `O' and `X'.

    Output

    Your program is to write to standard output. Print exactly one line for each test case. The line is to contain the score of the test case.

    The following shows sample input and output for five test cases.

    继续刷水题大业……

    思路很简单,一次AC,用函数完成就可以不用麻烦加清空语句了

    View Code
     1 #include<stdio.h>
     2 
     3 int score( const char string[] );
     4 
     5 int main()
     6 {
     7     char string[81];
     8     int n, i;
     9      
    10     scanf("%d", &n);
    11     getchar();
    12     
    13     for ( i = 0; i < n; i++ )
    14     {
    15         gets( string );
    16         printf( "%d\n", score( string ) );
    17     }
    18     
    19     return 0;
    20 }
    21 
    22 int score( const char string[] )
    23 {
    24     int i, j;
    25     int total = 0, temp = 0;
    26     
    27     for ( i = 0; string[i] != '\0'; i++ )
    28     {
    29         if ( string[i] == 'O' )
    30         {
    31             temp++;
    32             total = total + temp;
    33         }
    34         else
    35         {
    36             temp = 0;
    37         }
    38     }
    39     
    40     return total;
    41 }
  • 相关阅读:
    Eclipse配置Maven私服
    ubuntu下使用Nexus搭建Maven私服
    Ubuntu系统的Redis安装配置
    centos7.6安装dpdk-stable-19.11.10
    微软的分布式应用框架 Dapr Helloworld
    Caddy源码阅读(二)启动流程与 Event 事件通知
    Caddy源码阅读(一)Run详解
    Caddy 源码全解析
    假装前端工程师(一)Icework + GitHub pages 快速构建可自定义迭代开发的 react 网站
    caddy & grpc(3) 为 caddy 添加一个 反向代理插件
  • 原文地址:https://www.cnblogs.com/joyeecheung/p/2798426.html
Copyright © 2020-2023  润新知