• 排序 via F#


    冒泡排序:

    let rec bsort_asc s =
        let rec _bsort_asc = function
            |x1::x2::xs when x1 > x2 ->
                match _bsort_asc (x1::xs) with
                    |None -> Some(x2::x1::xs)
                    |Some xs2 -> Some(x2::xs2)
            |x1::x2::xs ->
                match _bsort_asc (x2::xs) with
                    |None -> None
                    |Some xs2 -> Some(x1::xs2)
            |_ -> None
        match _bsort_asc s with
            |None -> s
            |Some s2 -> bsort_asc s2
    

    快速排序:

    let rec quicksort = 
        function
        [] -> []
        |x::xs ->
            quicksort [for i in xs do if i < x then yield i]@
            x:: quicksort [for i in xs do if i >= x then yield i] 
    

    插入排序

    let rec insert x = function
        |[] -> [x]
        |y::tl when x > y -> y::(insert x tl)
        |l -> x::l
    let rec insertion_sort alist =
        match alist with
            |[] -> []
            |x::tl -> insert x (insertion_sort tl)
    

    希尔排序

    let shellsort f a =
        let N = Array.length a - 1
        let mutable width = 1
        while width <= N do
            width <- 3 * width + 1
        width <- width / 3
        while width >= 1 do
            for i = width to N do
                let v = a.[i]
                let mutable j = i
                while j >= width && (f a.[j - width] v) > 0 do
                    a.[j] <- a.[j-width]
                    j <- j - width
                a.[j] <- v
    let asc a b = (a - b)
    let dec a b = (b - a)
    

    直接选择排序

    let rec ssort_asc alist =
        match alist with
            |[] -> []
            |l ->
                let minrest l =
                    let rec aux list min acc =
                        match list with
                            [] -> min, acc
                            |h::t ->
                                if h < min then aux t h (min::acc)
                                else aux t min (h::acc)
                    aux (List.tail l)(List.head l)[]
                let (min, rest) = minrest l
                min :: (ssort_asc rest)
    

    堆排序

    let swap (a:_ []) i j =
        let temp = a.[i]
        a.[i] <- a.[j]
        a.[j] <- temp
    let sift cmp (a:_ []) start count =
        let rec loop root child =
            if root * 2 + 1 < count then
                let p = child < count - 1 && cmp a.[child] a.[child + 1] < 0
                let child = if p then child + 1 else child
                if cmp a.[root] a.[child] < 0 then
                    swap a root child
                    loop child (child * 2 + 1)
        loop start (start * 2 + 1)
    let heapsort cmp (a:_ []) =
        let n = a.Length
        for start = n/2 - 1 downto 0 do
            sift cmp a start n
        for term = n - 1 downto 1 do
            swap a term 0
            sift cmp a 0 term
    let asc a b = (a - b)
    let dec a b = (b - a)
    

    归并排序

    let split list =
        let rec aux l acc1 acc2 =
            match l with
                |[] -> (acc1, acc2)
                |[x] -> (x::acc1, acc2)
                |x::y::tail -> aux tail (x::acc1) (y::acc2)
        aux list [] []
    let rec merge l1 l2 =
        match (l1, l2) with
            |(x, []) -> x
            |([], y) -> y
            |(x::tx, y::ty) ->
                if x < y then x::merge tx l2
                else y::merge l1 ty
    let rec mergesort list =
        match list with
            |[] -> []
            |[x] -> [x]
            |_ ->
                let (l1, l2) = split list
                merge (mergesort l1) (mergesort l2)
    

    基数排序

    let radixSort (list:int array) : int array =
        let largestInt = Array.maxBy abs list
        let largestIntLen = if largestInt = 0 then 1 else (int(log10 (abs(largestInt |> double))) + 1)
        for i = 0 to largestIntLen - 1 do
            let mutable buckets = Array.create 19 (List.empty<int>)
            for number in list do
                let nthDigit nth number = int(abs(number) / int(10. ** (float(nth)))) % 10
                let nth = nthDigit i number
                if number < 0 then
                    buckets.[9 - nth] <- (List.append buckets.[9 - nth][number])
                elif number = 0 then
                    buckets.[9 + nth] <- (List.append buckets.[9 + nth][number])
            let mutable listIndex = 0
            for bucket in buckets do
                for num in bucket do
                    list.[listIndex] <- num
                    listIndex <- listIndex + 1
        list
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  • 原文地址:https://www.cnblogs.com/johnwii/p/4586809.html
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