package LeetCode_153 /** * 153. Find Minimum in Rotated Sorted Array https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/ Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Return the minimum element of this array. Example 1: Input: nums = [3,4,5,1,2] Output: 1 Example 2: Input: nums = [4,5,6,7,0,1,2] Output: 0 Example 3: Input: nums = [1] Output: 1 Constraints: 1. 1 <= nums.length <= 5000 2. -5000 <= nums[i] <= 5000 3. All the integers of nums are unique. 4. nums is sorted and rotated at some pivot * */ class Solution { /* * solution: Divide and conquer, check left side and right side of array, * Time complexity: O(logn), Space complexity: O(logn) (there are logn levels recursion) * */ fun findMin(nums: IntArray): Int { return findMin(nums, 0, nums.size - 1) } private fun findMin(nums: IntArray, left: Int, right: Int): Int { //is sorted if (nums[left] <= nums[right]) { return nums[left] } //compare left and right side val mid = left + (right - left) / 2 val leftSide = findMin(nums, left, mid) val rightSide = findMin(nums, mid+1, right) return Math.min(leftSide, rightSide) } }