• 398. Random Pick Index


    package LeetCode_398
    
    /**
     * 398. Random Pick Index
     * https://leetcode.com/problems/random-pick-index/description/
     *
     * Given an array of integers with possible duplicates, randomly output the index of a given target number.
     * You can assume that the given target number must exist in the array.
    Note:
    The array size can be very large. Solution that uses too much extra space will not pass the judge.
    
    Example:
    int[] nums = new int[] {1,2,3,3,3};
    Solution solution = new Solution(nums);
    
    // pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning.
    solution.pick(3);
    
    // pick(1) should return 0. Since in the array only nums[0] is equal to 1.
    solution.pick(1);
     * */
    class Solution(nums: IntArray) {
    
        /*
        for example input: {1,2,3,3,3}
        * return Iterable of IndexedValue with value,index like this:
        * 1=[0],2=[1],3=[2, 3, 4], then get random in values
        * */
        private val numWithIndex = nums.withIndex().groupBy({it.value},{it.index})
    
        fun pick(target: Int): Int {
            return numWithIndex[target]?.random()?: error("$target not found")
        }
    }
    
    /**
     * Your Solution object will be instantiated and called as such:
     * var obj = Solution(nums)
     * var param_1 = obj.pick(target)
     */
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  • 原文地址:https://www.cnblogs.com/johnnyzhao/p/13462031.html
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