• POJ 1129 Channel Allocation DFS 回溯


    Channel Allocation
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 15546   Accepted: 7871

    Description

    When a radio station is broadcasting over a very large area, repeaters are used to retransmit the signal so that every receiver has a strong signal. However, the channels used by each repeater must be carefully chosen so that nearby repeaters do not interfere with one another. This condition is satisfied if adjacent repeaters use different channels. 

    Since the radio frequency spectrum is a precious resource, the number of channels required by a given network of repeaters should be minimised. You have to write a program that reads in a description of a repeater network and determines the minimum number of channels required.

    Input

    The input consists of a number of maps of repeater networks. Each map begins with a line containing the number of repeaters. This is between 1 and 26, and the repeaters are referred to by consecutive upper-case letters of the alphabet starting with A. For example, ten repeaters would have the names A,B,C,...,I and J. A network with zero repeaters indicates the end of input. 

    Following the number of repeaters is a list of adjacency relationships. Each line has the form: 

    A:BCDH 

    which indicates that the repeaters B, C, D and H are adjacent to the repeater A. The first line describes those adjacent to repeater A, the second those adjacent to B, and so on for all of the repeaters. If a repeater is not adjacent to any other, its line has the form 

    A: 

    The repeaters are listed in alphabetical order. 

    Note that the adjacency is a symmetric relationship; if A is adjacent to B, then B is necessarily adjacent to A. Also, since the repeaters lie in a plane, the graph formed by connecting adjacent repeaters does not have any line segments that cross. 

    Output

    For each map (except the final one with no repeaters), print a line containing the minumum number of channels needed so that no adjacent channels interfere. The sample output shows the format of this line. Take care that channels is in the singular form when only one channel is required.

    Sample Input

    2
    A:
    B:
    4
    A:BC
    B:ACD
    C:ABD
    D:BC
    4
    A:BCD
    B:ACD
    C:ABD
    D:ABC
    0

    Sample Output

    1 channel needed.
    3 channels needed.
    4 channels needed. 
  • 相关阅读:
    lvs持久连接及防火墙标记实现多端口绑定服务
    LVS负载均衡器DR模型的实现
    CentOS 6.5结合busybox完成自制Linux系统及远程登录和nginx安装测试
    CentOS 6.5下的lamp环境rsyslog+MySQL+loganalyzer实现日志集中分析管理
    centos中selinux功能及常用服务配置
    网站遭遇CC及DDOS攻击紧急处理方案
    centos6.5下系统编译定制iptables防火墙扩展layer7应用层访问控制功能及应用限制QQ2016上网
    centos 6.5内核编译步骤及配置详解
    centos系统初始化流程及实现系统裁剪
    iptables实现网络防火墙及地址转换
  • 原文地址:https://www.cnblogs.com/joeylee97/p/6782702.html
Copyright © 2020-2023  润新知