• J


    Background 
    Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different genders and that they only interact with bugs of the opposite gender. In his experiment, individual bugs and their interactions were easy to identify, because numbers were printed on their backs. 
    Problem 
    Given a list of bug interactions, decide whether the experiment supports his assumption of two genders with no homosexual bugs or if it contains some bug interactions that falsify it.

    Input

    The first line of the input contains the number of scenarios. Each scenario starts with one line giving the number of bugs (at least one, and up to 2000) and the number of interactions (up to 1000000) separated by a single space. In the following lines, each interaction is given in the form of two distinct bug numbers separated by a single space. Bugs are numbered consecutively starting from one.

    Output

    The output for every scenario is a line containing "Scenario #i:", where i is the number of the scenario starting at 1, followed by one line saying either "No suspicious bugs found!" if the experiment is consistent with his assumption about the bugs' sexual behavior, or "Suspicious bugs found!" if Professor Hopper's assumption is definitely wrong.

    Sample Input

    2
    3 3
    1 2
    2 3
    1 3
    4 2
    1 2
    3 4

    Sample Output

    Scenario #1:
    Suspicious bugs found!
    
    Scenario #2:
    No suspicious bugs found!

    Hint

    Huge input,scanf is recommended.
     
     
     
     
    数据量大要用scanf
    #include<iostream>
    #include<map>
    #include<string>
    #include<algorithm>
    #include<cstdio>
    #include<queue>
    #include<cstring>
    #include<cmath>
    #include<vector>
    #include<set>
    #include<queue>
    #include<iomanip>
    #include<iostream>
    using namespace std;
    #define MAXN 2003
    #define INF 0x3f3f3f3f
    typedef long long LL;
    /*带权并查集,
    虫子只和不同性别交配,所以并查集距离为1,如果有不匹配,就标记
    */
    int pre[MAXN],rank[MAXN],n,m;
    int find(int x)
    {
        if(pre[x]==-1)
            return x;
        int fx = pre[x];
        pre[x] = find(pre[x]);
        rank[x] = (rank[x]+rank[fx])%2;
        return pre[x];
    }
    bool mix(int x,int y)
    {
        int fx = find(x),fy=find(y);
        if(fx==fy)
        {
            if(rank[x]!=(rank[y]+1)%2)
                return false;
            return true;
        }
        pre[fy] = fx;
        rank[fy] = (rank[x]-rank[y]+1+2)%2;
        return true;
    }
    void Init()
    {
        memset(rank,0,sizeof(rank));
        memset(pre,-1,sizeof(pre));
    }
    int main()
    {
        int t;
        scanf("%d",&t);
        for(int i=1;i<=t;i++)
        {
            scanf("%d%d",&n,&m);
            Init();
            int x,y;
            bool f = false;
            for(int j=0;j<m;j++)
            {
                scanf("%d%d",&x,&y);
                if(f) continue;
                if(!mix(x,y))
                    f = true;
            }
            printf("Scenario #%d:
    ",i);
            if(f)
                printf("Suspicious bugs found!
    ");
            else
                printf("No suspicious bugs found!
    ");
            printf("
    ");
        }
        return 0;
    }
  • 相关阅读:
    初识WEB:输入URL之后的故事
    ecshop ecmall shopex
    .net 4.5如何使用Async和Await进行异步编程
    C#中yield用法
    安装Ecshop首页出现报错:Only variables should be passed by referen
    Ecshop安装过程中的的问题:cls_image::gd_version()和不支持JPEG
    javascript 操作dom
    使用X-UA-Compatible来设置IE浏览器兼容模式
    createDocumentFragment
    ckfinder在IE10,IE9中的弹出框不能选择,或者不能上传解决方法
  • 原文地址:https://www.cnblogs.com/joeylee97/p/6603345.html
Copyright © 2020-2023  润新知