• [hdu5373 The shortest problem]模拟


    http://acm.hdu.edu.cn/showproblem.php?pid=5373

    思路:按题意来即可。

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    #include <map>
    #include <set>
    #include <cmath>
    #include <ctime>
    #include <deque>
    #include <queue>
    #include <stack>
    #include <vector>
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    
    using namespace std;
    
    #define X                   first
    #define Y                   second
    #define pb                  push_back
    #define mp                  make_pair
    #define all(a)              (a).begin(), (a).end()
    #define fillchar(a, x)      memset(a, x, sizeof(a))
    #define copy(a, b)          memcpy(a, b, sizeof(a))
    
    typedef long long ll;
    typedef pair<int, int> pii;
    typedef unsigned long long ull;
    
    //#ifndef ONLINE_JUDGE
    void RI(vector<int>&a,int n){a.resize(n);for(int i=0;i<n;i++)scanf("%d",&a[i]);}
    void RI(){}void RI(int&X){scanf("%d",&X);}template<typename...R>
    void RI(int&f,R&...r){RI(f);RI(r...);}void RI(int*p,int*q){int d=p<q?1:-1;
    while(p!=q){scanf("%d",p);p+=d;}}void print(){cout<<endl;}template<typename T>
    void print(const T t){cout<<t<<endl;}template<typename F,typename...R>
    void print(const F f,const R...r){cout<<f<<", ";print(r...);}template<typename T>
    void print(T*p, T*q){int d=p<q?1:-1;while(p!=q){cout<<*p<<", ";p+=d;}cout<<endl;}
    //#endif
    template<typename T>bool umax(T&a, const T&b){return b<=a?false:(a=b,true);}
    template<typename T>bool umin(T&a, const T&b){return b>=a?false:(a=b,true);}
    template<typename T>
    void V2A(T a[],const vector<T>&b){for(int i=0;i<b.size();i++)a[i]=b[i];}
    template<typename T>
    void A2V(vector<T>&a,const T b[]){for(int i=0;i<a.size();i++)a[i]=b[i];}
    
    const double PI = acos(-1.0);
    const int INF = 1e9 + 7;
    const double EPS = 1e-8;
    
    /* -------------------------------------------------------------------------------- */
    
    int get(int sum, int &x, int &mark) {
        if (sum == 0) {
            x = 0;
            mark = 1;
            return 0;
        }
        mark = 0;
        x = 0;
        int ans = 0;
        while (sum) {
            mark ^= 1;
            if (mark) ans += sum % 10;
            else ans -= sum % 10;
            x += sum % 10;
            sum /= 10;
        }
        return ans;
    }
    
    int main() {
    #ifndef ONLINE_JUDGE
        freopen("in.txt", "r", stdin);
        //freopen("out.txt", "w", stdout);
    #endif // ONLINE_JUDGE
        int n, t, cas = 0;
        while (cin >> n >> t, n != -1 && t != -1) {
            int mark, sum, ans;
            ans = get(n, sum, mark);
            for (int i = 0; i < t; i ++) {
                int x, buf = get(sum, x, mark);
                if (mark) ans = -ans + buf;
                else ans = ans + buf;
                sum += x;
            }
            printf("Case #%d: %s
    ", ++ cas, ans % 11? "No" : "Yes");
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/jklongint/p/4724088.html
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