• [hdu2222]ac自动机(模板)


    题意:一个文本串+多个模板串的匹配问题

    思路:裸的ac自动机。

      1 #pragma comment(linker, "/STACK:10240000,10240000")
      2 
      3 #include <iostream>
      4 #include <cstdio>
      5 #include <algorithm>
      6 #include <cstdlib>
      7 #include <cstring>
      8 #include <map>
      9 #include <queue>
     10 #include <deque>
     11 #include <cmath>
     12 #include <vector>
     13 #include <ctime>
     14 #include <cctype>
     15 #include <set>
     16 #include <bitset>
     17 #include <functional>
     18 #include <numeric>
     19 #include <stdexcept>
     20 #include <utility>
     21 
     22 using namespace std;
     23 
     24 #define mem0(a) memset(a, 0, sizeof(a))
     25 #define mem_1(a) memset(a, -1, sizeof(a))
     26 #define lson l, m, rt << 1
     27 #define rson m + 1, r, rt << 1 | 1
     28 #define define_m int m = (l + r) >> 1
     29 #define rep_up0(a, b) for (int a = 0; a < (b); a++)
     30 #define rep_up1(a, b) for (int a = 1; a <= (b); a++)
     31 #define rep_down0(a, b) for (int a = b - 1; a >= 0; a--)
     32 #define rep_down1(a, b) for (int a = b; a > 0; a--)
     33 #define all(a) (a).begin(), (a).end()
     34 #define lowbit(x) ((x) & (-(x)))
     35 #define constructInt4(name, a, b, c, d) name(int a = 0, int b = 0, int c = 0, int d = 0): a(a), b(b), c(c), d(d) {}
     36 #define constructInt3(name, a, b, c) name(int a = 0, int b = 0, int c = 0): a(a), b(b), c(c) {}
     37 #define constructInt2(name, a, b) name(int a = 0, int b = 0): a(a), b(b) {}
     38 #define pchr(a) putchar(a)
     39 #define pstr(a) printf("%s", a)
     40 #define sstr(a) scanf("%s", a)
     41 #define sint(a) scanf("%d", &a)
     42 #define sint2(a, b) scanf("%d%d", &a, &b)
     43 #define sint3(a, b, c) scanf("%d%d%d", &a, &b, &c)
     44 #define pint(a) printf("%d
    ", a)
     45 #define test_print1(a) cout << "var1 = " << a << endl
     46 #define test_print2(a, b) cout << "var1 = " << a << ", var2 = " << b << endl
     47 #define test_print3(a, b, c) cout << "var1 = " << a << ", var2 = " << b << ", var3 = " << c << endl
     48 #define mp(a, b) make_pair(a, b)
     49 #define pb(a) push_back(a)
     50 
     51 typedef long long LL;
     52 typedef pair<int, int> pii;
     53 typedef vector<int> vi;
     54 
     55 const int dx[8] = {0, 0, -1, 1, 1, 1, -1, -1};
     56 const int dy[8] = {-1, 1, 0, 0, 1, -1, 1, -1 };
     57 const int maxn = 3e4 + 7;
     58 const int md = 10007;
     59 const int inf = 1e9 + 7;
     60 const LL inf_L = 1e18 + 7;
     61 const double pi = acos(-1.0);
     62 const double eps = 1e-6;
     63 
     64 template<class T>T gcd(T a, T b){return b==0?a:gcd(b,a%b);}
     65 template<class T>bool max_update(T &a,const T &b){if(b>a){a = b; return true;}return false;}
     66 template<class T>bool min_update(T &a,const T &b){if(b<a){a = b; return true;}return false;}
     67 template<class T>T condition(bool f, T a, T b){return f?a:b;}
     68 template<class T>void copy_arr(T a[], T b[], int n){rep_up0(i,n)a[i]=b[i];}
     69 int make_id(int x, int y, int n) { return x * n + y; }
     70 
     71 int ans;
     72 
     73 struct AhoCorasickAutoMata {
     74     const static int SIGMA_SIZE = 26;
     75     const static int maxn = 250007;
     76     int cc;
     77     int ch[maxn][SIGMA_SIZE];
     78     int val[maxn], last[maxn], f[maxn];
     79 
     80     void clear() { cc = 0; mem0(val); mem0(ch); mem0(last); mem0(f); }
     81 
     82     int idex(char ch) { return ch - 'a'; }
     83 
     84     void Insert(char s[]) {
     85         int pos = 0;
     86         for(int i = 0; s[i]; i++) {
     87             int id = idex(s[i]);
     88             if(!ch[pos][id]) ch[pos][id] = ++ cc;
     89             pos = ch[pos][id];
     90         }
     91         val[pos] ++;
     92     }
     93 
     94     void print(int j) {
     95         if (j) {
     96             ans += val[j];
     97             val[j] = 0;//为了避免重复计数,需要在统计后置零
     98             print(last[j]);
     99         }
    100     }
    101 
    102     void find(char T[]) {
    103         int n = strlen(T);
    104         int j = 0;
    105         rep_up0(i, n) {
    106             int c = idex(T[i]);
    107             j = ch[j][c];
    108             if (val[j]) print(j);
    109             else {
    110                 if (last[j]) print(last[j]);
    111             }
    112         }
    113     }
    114 
    115     int getFail() {
    116         queue<int> q;
    117         f[0] = 0;
    118         rep_up0(c, SIGMA_SIZE) {
    119             int u = ch[0][c];
    120             if (u) {
    121                 f[u] = 0;
    122                 q.push(u);
    123                 last[u] = 0;
    124             }
    125         }
    126         while (!q.empty()) {
    127             int r = q.front(); q.pop();
    128             rep_up0(c, SIGMA_SIZE) {
    129                 int u = ch[r][c];
    130                 if (!u) {
    131                     ch[r][c] = ch[f[r]][c];
    132                     continue;
    133                 }
    134                 q.push(u);
    135                 int v = f[r];
    136                 while (v && !ch[v][c]) v = f[v];
    137                 f[u] = ch[v][c];
    138                 last[u] = val[f[u]]? f[u] : last[f[u]];
    139             }
    140         }
    141     }
    142 };
    143 
    144 AhoCorasickAutoMata ac;
    145 char str[55];
    146 char s[1000007];
    147 
    148 int main() {
    149     //freopen("in.txt", "r", stdin);
    150     int T, n;
    151     cin >> T;
    152     while (T--) {
    153         ac.clear();
    154         cin >> n;
    155         rep_up0(i, n) {
    156             scanf("%s", str);
    157             ac.Insert(str);
    158         }
    159         scanf("%s", s);
    160         ac.getFail();
    161         ans = 0;
    162         ac.find(s);
    163         cout << ans << endl;
    164     }
    165     return 0;
    166 }
    View Code
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  • 原文地址:https://www.cnblogs.com/jklongint/p/4471502.html
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