• django登录功能(简单在POST请求)


    第一  先在templates中创立index.html

    !DOCTYPE html>
    
    <head>
        <meta charset="UTF-8">
        <title>Django Page</title>
    </head>
    <body>
        <h1>登录页面</h1>
        <form method="post" action="/login_submit/">
            <input name="username" type="text" placeholder="username"><br>
            <input name="password" type="password" placeholder="password"><br>
            {{ error }}<br>
            <button id="btn" type="submit">登录</button>
            {% csrf_token %}
    
        </form>
    </body>
    </html>

    第二步  关联相关路径 这里路径为http://127.0.0.1:8000/login_submit/

    在url.py中

    urlpatterns = [
        url(r'^admin/', admin.site.urls),
        url(r'^index/$', views.index),
        url(r'^login_submit/$', views.login_submit),

    第三步 定义动作(POST处理登录请求)

    在view.py

     1 def index(request):
     2     return render(request, 'index.html')
     3 def login_submit(request):
     4     if request.method == 'POST':
     5         username = request.POST.get('username', '')
     6         password =request.POST.get('password', '')
     7         if username == 'admin' and password == 'admin123':
     8             return HttpResponse('login success!')
     9         else:
    10             return render(request,'index.html',{'error':'username or password error'})
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  • 原文地址:https://www.cnblogs.com/jjj-fly/p/6832837.html
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