本来想将写的代码挂在crontab下运行,谁知道无法运行,没有任何输出,试着用ls -al >> 1.log试了一下,确定crontab是正常运行的。
从网站上找了下问题,原因出在crontab启动的程序并不会加载环境变量,因此像“java”这种命令是无法启动的。
解决方案就是讲java换做具体的java路径。
步骤如下:
1. 运行命令crontab -e加入要运行的命令,并配置其运行频次
30 01 * * * /opt/changedig/app/module/rcproject/rcproject.sh
2. 修改启动脚本,将java路径换做绝对路径
#!/bin/sh WORK_DIR="/opt/changedig/app/module/rcproject" MYNAME="rcproject" pidfile=.$MYNAME.pid if test -f $WORK_DIR/$pidfile then # See if a process is running with that process id pid=`cat $WORK_DIR/$pidfile` if test -n "$pid" then ps -ef|grep $MYNAME|grep -v grep|awk '{print $2}'|grep $pid > /dev/null if test $? -eq 0 then # The process is running ! printf "The process is running ! " exit 3 else # Try the ps listing again as it is not always reliable ps -ef|grep $MYNAME|grep -v grep|awk '{print $2}'|grep $pid > /dev/null if test $? -eq 0 then # The process is running ! printf "The process is running ! " exit 3 fi fi fi fi echo $$>$WORK_DIR/$pidfile # Check process is existence if [ ! -f $WORK_DIR/rcproject-0.0.1.jar ] ; then printf "Error: Can not find the file $WORK_DIR/rcproject-*.jar " return 2 fi /usr/local/java/jdk1.7.0_45/bin/java -jar $WORK_DIR/rcproject-0.0.1.jar
如此即可