Given two strings s and t which consist of only lowercase letters.
String t is generated by random shuffling string s and then add one more letter at a random position.
Find the letter that was added in t.
Example:
Input: s = "abcd" t = "abcde" Output: e Explanation: 'e' is the letter that was added.
题目标签:Hash Table | Bit Manipulation
题目给了我们两个string, s 和 t, 让我们找到 s 和 t 不同的那一个char。
利用bit manipulation,把所有t 的 char 加起来,把所有s 的减去,剩下的就是多出来的那个 char。
Java Solution:
Runtime beats 98.24%
完成日期:11/07/2017
关键词:Bit Manipulation
关键点:累加 t, 减去 s
1 class Solution 2 { 3 public char findTheDifference(String s, String t) 4 { 5 int charSum = 0; 6 7 for(char c: t.toCharArray()) 8 charSum += c; 9 10 for(char c: s.toCharArray()) 11 charSum -= c; 12 13 return (char) charSum; 14 } 15 }
参考资料:N/A
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