java正则提取字符串

Pattern p = Pattern.compile("CN=(\\S*?),");
	                      
	                        Matcher match = p.matcher(cert.getSubjectDN().getName());
	                        if (match.find()){
	                        	System.out.println(match.group(1));
	                        }

待查找的字符串内容:

CN=511027XXX01027325X, OU=UCIT, O=Soft

需要查找出：511027XXX01027325X