synchonizd解决安全性问题
package com.cppdy; class MyThread6 implements Runnable{ private Integer ticketCount=100; private Object ob=new Object(); @Override public void run() { while(ticketCount>0) { try { Thread.sleep(50); } catch (Exception e) { e.printStackTrace(); } sale(); } } public void sale() { synchronized (ob) { if(ticketCount>0) { System.out.println(Thread.currentThread().getName()+"卖出了第:"+(100-ticketCount+1)+"张票。"); ticketCount--; } } } } public class ThreadDemo6 { public static void main(String[] args) throws Exception{ MyThread6 mt = new MyThread6(); Thread thread1 = new Thread(mt,"窗口1"); Thread thread2 = new Thread(mt,"窗口2"); thread1.start(); thread2.start(); } }
线程安全问题产生的条件:要有两个线程以上;必须要对同一变量进行操作;必须代码块使用同一把锁
原理:一个拿到锁,其它线程进行等待;释放过后,其它线程才能访问,就是锁的竞争问题,也是死锁产生的条件