Overflow |
Write a program that reads an expression consisting of twonon-negative integer and an operator. Determine if either integer orthe result of the expression is too large to be represented as a``normal'' signed integer (typeinteger if you are workingPascal, type int if you are working in C).
Input
An unspecified number of lines. Each line will contain an integer, oneof the two operators+ or *, and another integer.
Output
For each line of input, print the input followed by 0-3 linescontaining as many of these three messages as are appropriate: ``firstnumber too big'', ``second number too big'', ``result too big''.
Sample Input
300 + 3 9999999999999999999999 + 11
Sample Output
300 + 3 9999999999999999999999 + 11 first number too big result too big
题意:输入num1 + 或 * num2
若num1大于int可表示的最大值, 那么输出"first number too big"
同理num2的话, 输出"second number too big"
最后还要判定结果是否溢出, 若溢出, 输出"result too big"
都没溢出, 那么就没输出~
AC代码:
#include<stdio.h> #include<stdlib.h> #define MAX 2147483647 int main() { char num1[600], num2[600]; char ch; double n1, n2; while(scanf("%s %c %s", num1, &ch, num2) != EOF) { printf("%s %c %s ", num1, ch, num2); n1 = atof(num1); n2 = atof(num2); if(n1 > MAX) printf("first number too big "); if(n2 > MAX) printf("second number too big "); if(ch == '+' && n1+n2 > MAX) printf("result too big "); if(ch == '*' && n1*n2 > MAX) printf("result too big "); } return 0; }