在本文中,我们主要介绍程序语言的内容,自我感觉有个不错的提议和大家分享下
Power Strings
Time Limit: 3000MS | Memory Limit: 65536K | |
Total Submissions: 26177 | Accepted: 10976 |
Description
Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer is defined in the normal way: a^0 = "" (the empty string) and a^(n+1) = a*(a^n).
Input
Each test case is a line of input representing s, a string of printable characters. The length of s will be at least 1 and will not exceed 1 million characters. A line containing a period follows the last test case.
Output
For each s you should print the largest n such that s = a^n for some string a.
Sample Input
abcd aaaa ababab .
Sample Output
1 4 3
Hint
This problem has huge input, use scanf instead of cin to avoid time limit exceed.
Source
其实这道标题的路思来自POJ 1961,提议先做做1961,做完以后这道标题就会很易容的决解了
/*************************************************************** > File Name: E:\我的程序\C语言\power.c > Author: SDUT_GYX > Mail: 2272902662@qq.com > Created Time: 2013/5/9 10:14:47 **************************************************************/ #include<stdio.h> #include <string.h> #include <math.h> char s1[1100000]; int next[1100000],dp[1100000]; int main() { void get_next(int l); int i,j,n,m,s,t,l; while(gets(s1)) { if(strcmp(s1,".")==0) { break; } l=strlen(s1); get_next(l); dp[0]=0; for(i=2;i<=l;i++) { n=next[i]; if(n+n==i) { dp[i-1]=n; }else if(n+n<i) { dp[i-1]=0; }else { dp[i-1]=dp[n-1]; } } if(dp[l-1]==0) { printf("1\n"); }else { printf("%d\n",l/dp[l-1]); } } return 0; } void get_next(int l) { int i,j; next[0]=-1; next[1]=0; for(i=2,j=0;i<=l;) { if(j==-1||s1[i-1]==s1[j]) { i++;j++; next[i-1]=j; }else { j=next[j]; } } }
文章结束给大家分享下程序员的一些笑话语录:
面试官:熟悉哪种语言
应聘者:JAVA
面试官:知道什么叫类么
应聘者:我这人实在,工作努力,不知道什么叫累
面试官:知道什么是包?
应聘者:我这人实在 平常不带包 也不用公司准备了
面试官:知道什么是接口吗?
应聘者:我这个人工作认真。从来不找借口偷懒
面试官:知道什么是继承么
应聘者:我是孤儿没什么可以继承的
面试官:知道什么叫对象么?
应聘者:知道,不过我工作努力,上进心强,暂时还没有打算找对象。
面试官:知道多态么?
应聘者:知道,我很保守的。我认为让心爱的女人为了自已一时的快乐去堕胎是不道德的行为!请问这和C#有什么关系??