一个python练习

问题描述：

有一对兔子，每隔3个月就生一对兔子，生下来的兔子也是每隔3个月就生兔子，以此类推。。。

用python模拟出来：

#!/usr/bin/python3
import random
import string


class APairOfRabbits():
    def __init__(self):
        self.age = 1
        self.malename = ''.join(random.sample(string.ascii_letters, 5))
        self.femalename = ''.join(random.sample(string.ascii_letters, 4))
        self.childs = []
        self.parent = None
    def getParentInfo(self):
        if (None == self.parent):
            return None
        else:
            print("ParentsName: %s" % self.parent.getName())
    def getChildsInfo(self):
        for child in self.childs:
            print("ChildsName:%s" % child.getName())
        print("")
    def info(self):
        print('%s and %s: age %d' % (self.malename, self.femalename, self.age))
        self.getParentInfo()
        self.getChildsInfo()

    def propagate(self):
        self.childs.append(APairOfRabbits())
        self.childs[-1].setParent(self)
    def getName(self):
        return self.malename + "-" + self.femalename
    def growUpOfMonth(self):
        self.age += 1
        if(0 == (self.age % 3)):
            self.propagate()

    def setParent(self, parent):
        self.parent = parent
    def getParent(self):
        return self.parent
    def getChilds(self):
        return self.childs

class RabbitsFamily():
    def __init__(self):
        self.rootRabbits = APairOfRabbits()
    def dfsUpdateState(self, parent = None):
        if None == parent:
            parent = self.rootRabbits
        for child in parent.getChilds():
            self.dfsUpdateState(child)
        parent.growUpOfMonth()
    def dfsShowState(self, parent = None):
        if None == parent:
            parent = self.rootRabbits
        parent.info()
        for child in parent.getChilds():
            self.dfsShowState(child)
    
rabbitsFamily = RabbitsFamily()
for i in range(55):
    rabbitsFamily.dfsUpdateState()
rabbitsFamily.dfsShowState()