• Coursera-Algotithms学习


    Week1 Job Interview Question

    Social network connectivity. Given a social network containing N members and a log file containing M timestamps at which times pairs of members formed friendships, design an algorithm to determine the earliest time at which all members are connected (i.e., every member is a friend of a friend of a friend ... of a friend). Assume that the log file is sorted by timestamp and that friendship is an equivalence relation. The running time of your algorithm should be MlogN or better and use extra space proportional to N.

     1 public class SocialNet {
     2     private int N;
     3     private String InputFileName;
     4     public SocialNet(int N,String InputFileName){
     5         this.N = N;
     6         this.InputFileName = InputFileName;
     7     }
     8     public String getTimeString(){
     9         WeightedQuickUnionUF wQUF = new WeightedQuickUnionUF(N);
    10         In fin = new In(InputFileName);
    11         while(fin.hasNextLine()){
    12             String[] lineSplit = fin.readLine().split(" ");
    13             wQUF.union(Integer.parseInt(lineSplit[1]), Integer.parseInt(lineSplit[2]));
    14             if(wQUF.count() == 1){
    15                 return lineSplit[0];
    16             }
    17         }
    18         return "Never";
    19     }
    20     public static void main(String[] args) {
    21         // TODO Auto-generated method stub
    22         SocialNet sn = new SocialNet(10,"SocialNetInput.txt");
    23         System.out.println(sn.getTimeString());
    24     }
    25 }

     input File:

    20130101 0 2
    20130201 0 4
    20130301 2 3
    20130401 3 4
    20130501 4 5
    20130601 3 6
    20130701 5 6
    20130801 2 6
    20130901 1 2
    20131001 7 3
    20131101 0 9
    20131201 4 8
    20131202 4 3
  • 相关阅读:
    js/css 伪类, 获取伪类样式
    JS 盒子模型
    python坑之input获取字符串
    configpraser模块
    类的特殊成员&反射&异常处理
    面向对象
    员工信息表
    re正则表达式
    PyCharm教程
    递归实现jsonTree
  • 原文地址:https://www.cnblogs.com/jianboqi/p/3555037.html
Copyright © 2020-2023  润新知