• Swift小技巧(二)


    .如何解决闭包内部的循环引用问题
     //通过定义捕获列表解决
    lazy var someClosure: Void -> String = {
        //unowned:无主引用  weak:弱引用
        [unowned self, weak delegate = self.delegate!] in
        // 这里是闭包的函数体
    }
        
    
    .如何获得某个变量的类型字符串
     let string = "Hello"
    let stringArray = ["one", "two"]
    let dictionary = ["key": 2]
    
    //打印具体内容
    print(string)//Hello
    print(stringArray)//["one", "two"]
    print(dictionary)//["key": 2]
    //打印类型
    print(type(of: string))//"String"
    print(type(of: stringArray))//Array<String>
    print(type(of: dictionary))//Dictionary<String, Int>
    //获得类型字符串
    String(describing: type(of: string)) // "String"
    String(describing: type(of: stringArray)) // "Array<String>"
    String(describing: type(of: dictionary)) // "Dictionary<String, Int>"
    //获得完整的类型字符串
    String(reflecting: type(of: string)) // "Swift.String"
    String(reflecting: type(of: stringArray)) // "Swift.Array<Swift.String>"
    String(reflecting: type(of: dictionary)) // "Swift.Dictionary<Swift.String, Swift.Int>"
        
    
    .如何查找数组内部某个元素或者某些元素
     class Person {
        let name: String
        let age: Int
        init(name: String, age: Int) {
            self.name = name
            self.age = age
        }
    }
    let p1 = Person(name: "a", age: 1)
    let p2 = Person(name: "b", age: 2)
    let p3 = Person(name: "c", age: 3)
    let p4 = Person(name: "c", age: 31)
    let array = [p1,p2,p3,p4]
    //可以获得p1的下标为0
    var result = array.firstIndex { $0 === p1 }
    print(result!)
    //通过元素内部的某个属性来查找index
    result = array.firstIndex { $0.name == "c" }
    print(result!)
    //index只会返回第一个查找到的,查找多个,需要使用filter
    let contents = array.filter { $0.name == "c" }
    contents.count//contents会包含所有name=c的值
    
    生成指定位数的整数或者小数,不足位数以0补充
     //指定位数字,不足的位数以0补充
    extension Int {
        func format(f: String) -> String {
            return String(format: "%(f)d", self)
        }
    }
    //保留指定位小数,不足位数以0补充
    extension Double {
        func format(f: String) -> String {
            return String(format: "%(f)f", self)
        }
    }
    //使用
    print(8.format(f: "06"))//000008
    print(8.format(f: "02"))//08
    print(9999.format(f: "02"))//9999
    print(0.12345.format(f: ".2"))//0.12
    print(0.1.format(f: ".4"))//0.1000
        
    
    对数组内元素,按照指定属性指定规则进行排序
     struct ImageFile {
        var name: String
        var ID: Int
    }
    
    let image1 = ImageFile(name: "a.jpg", ID: 3)
    let image2 = ImageFile(name: "c.jpg", ID: 2)
    let image3 = ImageFile(name: "b.jpg", ID: 1)
    var images = [image1, image2, image3]
    images.sort { $0.ID > $1.ID }//从大到小排序
    images.sort { $0.name < $1.name }//从小到大排序
        
    
    如何替换字符串中某个特定字符
     let string = "This is my string"
    //替换" "成"-",最终结果为:"This-is-my-string"
    
    //方法一
    let newString1 = string.replacingOccurrences(of: " ", with: "-")
    //方法二
    let toArray = string.components(separatedBy: " ")
    let newString2 = toArray.joined(separator: "+")
    //方法三
    let newString3 = String(string.characters.map {
        $0 == " " ? "+" : $0
    })
        
    
    如何发出http请求

    ss1

     let url = URL(string: "http://www.baidu.com")
    let task = URLSession.shared.dataTask(with: url!) { (data, response, error) in
        print(String(data: data!, encoding: .utf8))
    }
    task.resume()
        
    
    如何修改imageview中image的颜色

    ss1

     override func viewDidLoad() {
            super.viewDidLoad()
            let imageView = UIImageView(frame: CGRect(x: 10, y: 100,  20, height: 20))
            imageView.image = UIImage(named: "ADD")
            changeTintColor(imageView: imageView, color: .red)
            view.addSubview(imageView)
        }
        
        func changeTintColor(imageView: UIImageView, color: UIColor) {
            imageView.image = imageView.image!.withRenderingMode(.alwaysTemplate)
            imageView.tintColor = color
        }
        
    
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  • 原文地址:https://www.cnblogs.com/jiafei/p/13793529.html
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