Buy the souvenirs
Time Limit: 10000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Problem Description
When
the winter holiday comes, a lot of people will have a trip. Generally,
there are a lot of souvenirs to sell, and sometimes the travelers will
buy some ones with pleasure. Not only can they give the souvenirs to
their friends and families as gifts, but also can the souvenirs leave
them good recollections. All in all, the prices of souvenirs are not
very dear, and the souvenirs are also very lovable and interesting. But
the money the people have is under the control. They can’t buy a lot,
but only a few. So after they admire all the souvenirs, they decide to
buy some ones, and they have many combinations to select, but there are
no two ones with the same kind in any combination. Now there is a blank
written by the names and prices of the souvenirs, as a top coder all
around the world, you should calculate how many selections you have, and
any selection owns the most kinds of different souvenirs. For instance:
And you have only 7 RMB, this time you can select any combination with 3 kinds of souvenirs at most, so the selections of 3 kinds of souvenirs are ABC (6), ABD (7). But if you have 8 RMB, the selections with the most kinds of souvenirs are ABC (6), ABD (7), ACD (8), and if you have 10 RMB, there is only one selection with the most kinds of souvenirs to you: ABCD (10).
And you have only 7 RMB, this time you can select any combination with 3 kinds of souvenirs at most, so the selections of 3 kinds of souvenirs are ABC (6), ABD (7). But if you have 8 RMB, the selections with the most kinds of souvenirs are ABC (6), ABD (7), ACD (8), and if you have 10 RMB, there is only one selection with the most kinds of souvenirs to you: ABCD (10).
Input
For the first line, there is a T means the number cases, then T cases follow.
In each case, in the first line there are two integer n and m, n is the number of the souvenirs and m is the money you have. The second line contains n integers; each integer describes a kind of souvenir.
All the numbers and results are in the range of 32-signed integer, and 0<=m<=500, 0<n<=30, t<=500, and the prices are all positive integers. There is a blank line between two cases.
In each case, in the first line there are two integer n and m, n is the number of the souvenirs and m is the money you have. The second line contains n integers; each integer describes a kind of souvenir.
All the numbers and results are in the range of 32-signed integer, and 0<=m<=500, 0<n<=30, t<=500, and the prices are all positive integers. There is a blank line between two cases.
Output
If
you can buy some souvenirs, you should print the result with the same
formation as “You have S selection(s) to buy with K kind(s) of
souvenirs”, where the K means the most kinds of souvenirs you can buy,
and S means the numbers of the combinations you can buy with the K kinds
of souvenirs combination. But sometimes you can buy nothing, so you
must print the result “Sorry, you can't buy anything.”
Sample Input
2
4 7
1 2 3 4
4 0
1 2 3 4
Sample Output
You have 2 selection(s) to buy with 3 kind(s) of souvenirs.
Sorry, you can't buy anything.
Author
wangye
Source
思路:在01背包的方案dp方程再加一维,记录K;
dp[i][t]+=dp[i-a[j]][t-1];
#include<bits/stdc++.h> using namespace std; #define ll long long #define esp 0.00000000001 const int N=1e3+10,M=1e6+10,inf=1e9+10,mod=1000000007; int a[N]; int dp[N][N]; int main() { int x,y,z,i,t; int T; scanf("%d",&T); while(T--) { memset(dp,0,sizeof(dp)); scanf("%d%d",&x,&y); for(i=1;i<=x;i++) scanf("%d",&a[i]); dp[0][0]=1; for(i=1;i<=x;i++) { for(t=y;t>=a[i];t--) { for(int j=0;j<x;j++) dp[t][j+1]+=dp[t-a[i]][j]; } } int ans=0; for(t=x;t>=0;t--) { ans=0; for(i=0;i<=y;i++) ans+=dp[i][t]; if(ans>0)break; } if(t>0) printf("You have %d selection(s) to buy with %d kind(s) of souvenirs. ",ans,t); else printf("Sorry, you can't buy anything. "); } return 0; }