Write a program to find the node at which the intersection of two singly linked lists begins.
For example, the following two linked lists:
A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3
begin to intersect at node c1.
Notes:
- If the two linked lists have no intersection at all, return
null
. - The linked lists must retain their original structure after the function returns.
- You may assume there are no cycles anywhere in the entire linked structure.
- Your code should preferably run in O(n) time and use only O(1) memory.
//Time: O(n), Space: O(1) public ListNode getIntersectionNode(ListNode headA, ListNode headB) { if (headA == null || headB == null) { return null; } int lenA = getLen(headA); int lenB = getLen(headB); if (lenA > lenB) { headA = forward(headA, lenA - lenB); } else { headB = forward(headB, lenB - lenA); } while (headA != null && headB != null) { if (headA == headB) { return headA; } headA = headA.next; headB = headB.next; } return null; } private int getLen(ListNode head) { int count = 1; while (head != null) { head = head.next; count++; } return count; } private ListNode forward(ListNode head, int step) { while (step > 0) { head = head.next; step--; } return head; }