Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Example:
Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4
//Time: O(n), Space: O(n) //也可以用recusive但是时间复杂度很高,此处略 public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if (l1 == null && l2 == null) { return null; } if (l1 == null || l2 == null) { return l1 == null ? l2 : l1; } ListNode head = new ListNode(0); ListNode dummy = head; while (l1 != null && l2 != null) { if (l1.val < l2.val) { head.next = new ListNode(l1.val); l1 = l1.next; } else {//这里不用单独把l1.val = l2.val单独拿出来,因为即使相等append完一个数就错位了,可以继续 head.next = new ListNode(l2.val); l2 = l2.next; } head = head.next; } if (l1 != null) { head.next = l1; } if (l2 != null) { head.next = l2; } return dummy.next; }