android MotionEvent 获取长按压时间长

思路：

1.记录ACTION_DOWN的aX, aY坐标；

2.在ACTION_MOVE判断是否移动，移动则取消记录时间，没移动就记录；

3.记录时间，按下坐标，移动坐标分别显示在TextView aa, bb, cc；

//声明

public class MainActivity extends ActionBarActivity {
    private static TextView aa, bb, cc;
    private float atime;
    private float aX, aY;
    private boolean mPressBreak = false;

//指定

aa = (TextView) findViewById(R.id.textView1);
bb = (TextView) findViewById(R.id.textView2); 
cc = (TextView) findViewById(R.id.textView3);

//获取按压时间长

@Override
    public boolean onTouchEvent(MotionEvent event) {
        // TODO Auto-generated method stub
        super.onTouchEvent(event);
        String str = "";
        switch (event.getAction()) {
        case MotionEvent.ACTION_DOWN:
            aX = event.getX();
            aY = event.getY();
            str = String.valueOf(aX) + " , " + String.valueOf(aY);
            bb.setText(str);
            mPressBreak = false;
            break;
        case MotionEvent.ACTION_MOVE:

            atime = (event.getEventTime() - event.getDownTime()) / 1000;
            str = String.valueOf(event.getX()) + " , "
                    + String.valueOf(event.getY());
            if ((Math.abs((event.getX() - aX)) > 10)
                    || (Math.abs(event.getY() - aY) > 10)) {
                atime = 0;
                mPressBreak = true;
            }
            break;

        }

        if (!mPressBreak) {
            aa.setText(String.valueOf((int) (atime)));
            cc.setText(str);
        }

        return true;
    }