• 【LeetCode】165. Compare Version Numbers


    题目:

    Compare two version numbers version1 and version2.
    If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

    You may assume that the version strings are non-empty and contain only digits and the . character.
    The . character does not represent a decimal point and is used to separate number sequences.
    For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

    Here is an example of version numbers ordering:

    0.1 < 1.1 < 1.2 < 13.37

    提示:

    这道题难就难在考虑的是否缜密,这里列举出一些典型的测试用例:

    • ["01", "1"]
    • ["10.6.5", "10.6"]
    • ["1.0", "1"]

    代码:

    我自己的实现方法(比较臃肿,不推荐):

    class Solution {
    public:
        int compareVersion(string version1, string version2) {
            int v1, v2, pos1, pos2;
            while (true) {
                if (version1.size() == 0) {
                    if (version2.size() == 0) return 0;
                    else version1 = "0";
                }
                else {
                    if (version2.size() == 0) version2 = "0";
                }
    
                pos1 = version1.find(".");
                if (pos1 > -1) {
                    v1 = atoi(version1.substr(0, pos1).c_str());
                    version1 = version1.substr(pos1 + 1, version1.size() - 1);
                }
                else {
                    v1 = atoi(version1.c_str());
                    version1 = "";
                }
                pos2 = version2.find(".");
                if (pos2 > -1) {
                    v2 = atoi(version2.substr(0, pos2).c_str());
                    version2 = version2.substr(pos2 + 1, version2.size() - 1);
                }
                else {
                    v2 = atoi(version2.c_str());
                    version2 = "";
                }
                if (v1 > v2) return 1;
                if (v1 < v2) return -1;
            }
    
        }
    };

    论坛里某大神的方法(非常简洁,推荐):

    class Solution {
    public:
        int compareVersion(string version1, string version2) {
            for (auto& w : version1) if (w == '.') w = ' ';
            for (auto& w : version2) if (w == '.') w = ' ';
            istringstream s1(version1), s2(version2);
            while (true) {
                int n1, n2;
                if (!(s1 >> n1)) n1 = 0;
                if (!(s2 >> n2)) n2 = 0;
                if (!s1 && !s2) return 0;
                if (n1 < n2) return -1;
                if (n1 > n2) return 1;
            }
        }
    };
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  • 原文地址:https://www.cnblogs.com/jdneo/p/4795784.html
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