一、L的3.41次方+40000L的1.56次方=21780889,帮我算出L
解决方案,正常算,确实不会算,采用无限趋近法,得到近似值,编程采用递归
import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.Console; import java.io.File; import java.io.FileReader; import java.io.FileWriter; import java.util.ArrayList; import java.util.List; public class Io { public static void main(String args[]) throws Exception{ new Io().operate(1, 1000, 1); } private void operate(double min,double max,double add){ boolean bool = true; List<Double> list = new ArrayList<Double>(); List<Double> listSub = new ArrayList<Double>(); double sub = 0; for(double i=min;i<max;i+=add){ list.add(i); double result = Math.pow(i, 3.41) + Math.pow(i, 1.56)*40000; if((sub = Math.abs(result-21780889)) < 0.001){ bool = false; break; }else{ listSub.add(sub); } } if(bool){ int pos = 0; for(int j=0;j<listSub.size()-1;j++){ pos = j; if(listSub.get(j)<listSub.get(j+1)){ break; } } operate(list.get(pos-1), list.get(pos+1), add/10); }else{ System.out.println("最终结果:"+list.get(list.size()-1)+" "+sub); } } }
二、
import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.Console; import java.io.File; import java.io.FileReader; import java.io.FileWriter; import java.util.ArrayList; import java.util.List; public class Io { public static void main(String args[]) throws Exception{ String path = "c:\\weibo.txt"; String content = null; String account[]; //read the txt; content = new Io().readTxt(path); // show all of the accounts on the screen account = content.split("#"); for(int i=0,len=account.length;i<len;i++){ System.out.println(account[i]); } // " " replace # and save in the floder content = content.replace("#", " "); new Io().writeTxt("c:\\chulihou.txt", content); //chulihou.txt这出题人也够NB嗒 //delete the floder File file = new File(path); file.delete(); } private String readTxt(String path) throws Exception{ StringBuffer string = new StringBuffer(); String temp; BufferedReader in =new BufferedReader(new FileReader(path)); while((temp = in.readLine()) != null){ string.append(temp); } in.close(); return string.toString(); } private void writeTxt(String path, String content) throws Exception{ FileWriter fw=new FileWriter( path ); BufferedWriter bw =new BufferedWriter(fw); bw.write( content ); bw.flush(); bw.close(); fw.close(); } }