Question :
Given a binary tree, find its minimum depth.
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
Anwser 1 :
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int minDepth(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function if (root == NULL) return 0; int left = minDepth(root->left) + 1; int right = minDepth(root->right) + 1; // leaf if (left == 1 || right == 1) return left > right ? left : right; return left < right ? left : right; } };
Anwser 2 :
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int minDepth(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function if (root == NULL) return 0; int depth = 1; queue <TreeNode *> current; queue <TreeNode *> next; current.push(root); while (!current.empty()) { while (!current.empty()) { TreeNode *n = current.front(); current.pop(); if (n->left==NULL && n->right == NULL) return depth; if (n->left) next.push(n->left); if (n->right) next.push(n->right); } queue <TreeNode *> t; // init queue current = next; next = t; depth += 1; } return depth; } };