Wooden Sticks
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 27437 | Accepted: 11926 |
Description
There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the
machine will need no setup time for a stick of length l' and weight w'
if l <= l' and w <= w'. Otherwise, it will need 1 minute for
setup.
You are to find the minimum setup time to process a given pile of n
wooden sticks. For example, if you have five sticks whose pairs of
length and weight are ( 9 , 4 ) , ( 2 , 5 ) , ( 1 , 2 ) , ( 5 , 3 ) ,
and ( 4 , 1 ) , then the minimum setup time should be 2 minutes since
there is a sequence of pairs ( 4 , 1 ) , ( 5 , 3 ) , ( 9 , 4 ) , ( 1 , 2
) , ( 2 , 5 ) .
Input
The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1 <= n <= 5000 , that represents the number of wooden sticks in the test case, and the second line contains 2n positive integers l1 , w1 , l2 , w2 ,..., ln , wn , each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.
Output
The output should contain the minimum setup time in minutes, one per line.
Sample Input
3 5 4 9 5 2 2 1 3 5 1 4 3 2 2 1 1 2 2 3 1 3 2 2 3 1
Sample Output
2 1 3
思路:这道题并不难,只是要把题目想清楚,就是简单的贪心和略带一点的动态规划;
但是现在由于 POJ 维修不能提交,明天再提交了看
1 #include <cstdio> 2 #include <cstring> 3 #include <algorithm> 4 #include <iostream> 5 #define MAX_N 10005 6 using namespace std; 7 8 int n; 9 10 struct Wood 11 { 12 int l; 13 int w; 14 int used; 15 }wood[MAX_N]; 16 17 bool cmp(const Wood &a,const Wood &b){ 18 if(a.l==b.l) return a.w<b.w; 19 else return a.l<b.l; 20 } 21 22 int main(void){ 23 int T; 24 scanf("%d",&T); 25 for(int m=0;m<T;m++){ 26 int ans=0; 27 scanf("%d",&n); 28 for(int j=0;j<n;j++){ 29 scanf("%d",&wood[j].l); 30 scanf("%d",&wood[j].w); 31 wood[j].used=0; 32 } 33 sort(wood,wood+n,cmp); 34 35 for(int i=0;i<n;i++){ 36 int last=wood[i].w; 37 if(!wood[i].used){ 38 for(int j=i+1;j<n;j++){ 39 if(wood[j].w>=last&&(!wood[j].used)){ 40 wood[j].used=1; 41 last=wood[j].w; 42 } 43 } 44 ans++; 45 } 46 } 47 printf("%d ",ans); 48 } 49 50 return 0; 51 }