• Java AmericanFlagSort


    Java AmericanFlagSort

    /**
     * <html>
     * <body>
     *  <P> Copyright 1994-2018 JasonInternational </p>
     *  <p> All rights reserved.</p>
     *  <p> Created on 2018年4月10日 </p>
     *  <p> Created by Jason</p>
     *  </body>
     * </html>
     */
    package cn.ucaner.algorithm.sorts;
    
    /**
     * An American flag sort is an efficient, in-place variant of radix sort that
     * distributes items into hundreds of buckets. Non-comparative sorting
     * algorithms such as radix sort and American flag sort are typically used to
     * sort large objects such as strings, for which comparison is not a unit-time
     * operation. 
     * <p>
     * Family: Bucket.<br>
     * Space: In-place.<br>
     * Stable: False.<br>
     * <p>
     * Average case = O(n*k/d)<br>
     * Worst case = O(n*k/d)<br>
     * Best case = O(n*k/d)<br>
     * <p>
     * NOTE: n is the number of digits and k is the average bucket size
     * <p>
     * @see <a href="https://en.wikipedia.org/wiki/American_flag_sort">American Flag Sort (Wikipedia)</a>
     * <br>
     * @author Justin Wetherell <phishman3579@gmail.com>
     */
    public class AmericanFlagSort {
    
        private static final int NUMBER_OF_BUCKETS = 10; // 10 for base 10 numbers
    
        private AmericanFlagSort() { }
    
        public static Integer[] sort(Integer[] unsorted) {
            int numberOfDigits = getMaxNumberOfDigits(unsorted); // Max number of digits
            int max = 1;
            for (int i = 0; i < numberOfDigits - 1; i++)
                max *= 10;
            sort(unsorted, 0, unsorted.length, max);
            return unsorted;
        }
    
        public static void sort(Integer[] unsorted, int start, int length, int divisor) {
            // First pass - find counts
            int[] count = new int[NUMBER_OF_BUCKETS];
            int[] offset = new int[NUMBER_OF_BUCKETS];
            int digit = 0;
            for (int i = start; i < length; i++) {
                int d = unsorted[i];
                digit = getDigit(d, divisor);
                count[digit]++;
            }
            offset[0] = start + 0;
            for (int i = 1; i < NUMBER_OF_BUCKETS; i++) {
                offset[i] = count[i - 1] + offset[i - 1];
            }
            // Second pass - move into position
            for (int b = 0; b < NUMBER_OF_BUCKETS; b++) {
                while (count[b] > 0) {
                    int origin = offset[b];
                    int from = origin;
                    int num = unsorted[from];
                    unsorted[from] = -1;
                    do {
                        digit = getDigit(num, divisor);
                        int to = offset[digit]++;
                        count[digit]--;
                        int temp = unsorted[to];
                        unsorted[to] = num;
                        num = temp;
                        from = to;
                    } while (from != origin);
                }
            }
            if (divisor > 1) {
                // Sort the buckets
                for (int i = 0; i < NUMBER_OF_BUCKETS; i++) {
                    int begin = (i > 0) ? offset[i - 1] : start;
                    int end = offset[i];
                    if (end - begin > 1)
                        sort(unsorted, begin, end, divisor / 10);
                }
            }
        }
    
        private static int getMaxNumberOfDigits(Integer[] unsorted) {
            int max = Integer.MIN_VALUE;
            int temp = 0;
            for (int i : unsorted) {
                temp = (int) Math.log10(i) + 1;
                if (temp > max)
                    max = temp;
            }
            return max;
        }
    
        private static int getDigit(int integer, int divisor) {
            return (integer / divisor) % 10;
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/jasonandy/p/9243193.html
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