例题来源于 b站灰灰
https://space.bilibili.com/51950540/dynamic?spm_id_from=444.41.0.0
场景1 主线程等待子线程执行完毕后并获取结果而后执行
public class Test {
public static void main(String[] args) {
SmallTools.printTimeAndThread("小白进入餐厅");
SmallTools.printTimeAndThread("小白点了 番茄炒蛋+一碗米饭");
CompletableFuture<String> cf1 = CompletableFuture.supplyAsync(() -> {
SmallTools.printTimeAndThread("厨师炒菜");
SmallTools.sleep(200);
SmallTools.printTimeAndThread("厨师打饭");
SmallTools.sleep(300);
return "番茄鸡蛋+米饭做好啦";
});
SmallTools.printTimeAndThread("小白在打王者");
SmallTools.printTimeAndThread(String.format("%s,小白开吃", cf1.join()));
}
static class SmallTools {
public static void sleep(long millis) {
try {
Thread.sleep(millis);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
public static String printTimeAndThread(String tag) {
String result = new StringJoiner("\t|\t")
.add(String.valueOf(System.currentTimeMillis()))
.add(String.valueOf(Thread.currentThread().getId()))
.add(Thread.currentThread().getName())
.add(tag)
.toString();
System.out.println(result);
return result;
}
}
}
- supplyAsync 用来开启一个异步任务
其中 CompletableFuture.supplyAsync 用来开启一个子线程,其方法执行完毕后返回一个结果,主线程可以通过调用 cf1.join() 来获取执行结果
场景2 主线程等待多个子线程执行完毕后执行,而子线程分先后顺序,线程1需要等待线程2执行完毕后再执行
public class Test {
public static void main(String[] args) {
SmallTools.printTimeAndThread("小白进入餐厅");
SmallTools.printTimeAndThread("小白点了 番茄炒蛋+一碗米饭");
CompletableFuture<String> cf1 = CompletableFuture.supplyAsync(() -> {
SmallTools.printTimeAndThread("厨师炒菜");
SmallTools.sleep(1200);
return "番茄鸡蛋";
}).thenCompose(dish -> CompletableFuture.supplyAsync(() -> {
SmallTools.printTimeAndThread("服务员打饭");
SmallTools.sleep(300);
return dish + "+米饭做好啦";
}));
SmallTools.printTimeAndThread("小白在打王者");
SmallTools.printTimeAndThread(String.format("%s,小白开吃", cf1.join()));
}
static class SmallTools {
public static void sleep(long millis) {
try {
Thread.sleep(millis);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
public static String printTimeAndThread(String tag) {
String result = new StringJoiner("\t|\t")
.add(String.valueOf(System.currentTimeMillis()))
.add(String.valueOf(Thread.currentThread().getId()))
.add(Thread.currentThread().getName())
.add(tag)
.toString();
System.out.println(result);
return result;
}
}
}
- thenCompose 用来连接两个任务
第二个任务需要获取第一个任务的返回结果后返回
场景3 子线程等待两个子线程执行完毕后,再将这两个子线程的执行结果统一返回
public class Test {
public static void main(String[] args) {
SmallTools.printTimeAndThread("小白进入餐厅");
SmallTools.printTimeAndThread("小白点了 番茄炒蛋+一碗米饭");
CompletableFuture<String> cf1 = CompletableFuture.supplyAsync(() -> {
SmallTools.printTimeAndThread("厨师炒菜");
SmallTools.sleep(200);
return "番茄鸡蛋";
}).thenCombine(CompletableFuture.supplyAsync(() -> {
SmallTools.printTimeAndThread("服务员煮饭");
SmallTools.sleep(200);
return "";
}), (dish, rice) -> {
SmallTools.printTimeAndThread("服务员打饭");
return dish + rice;
});
SmallTools.printTimeAndThread("小白在打王者");
SmallTools.printTimeAndThread(String.format("%s,小白开吃", cf1.join()));
}
static class SmallTools {
public static void sleep(long millis) {
try {
Thread.sleep(millis);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
public static String printTimeAndThread(String tag) {
String result = new StringJoiner("\t|\t")
.add(String.valueOf(System.currentTimeMillis()))
.add(String.valueOf(Thread.currentThread().getId()))
.add(Thread.currentThread().getName())
.add(tag)
.toString();
System.out.println(result);
return result;
}
}
}
- thenCombine 连接两个子线程,而后将两个线程的执行结果合并后统一输入