题目大意:
求割点;
基本思路:
tarjan算法,套板子
代码如下:
#include<iostream> #include<string> #include<vector> #include<queue> #include<algorithm> #include<cstdio> #include<cstring> #include<cmath> using namespace std; const int inf = 0x3f3f3f3f; const int maxn = 110+10; bool vis[maxn]; int dfn[maxn],low[maxn],cut[maxn]; vector<int>gra[maxn]; int cnt=0; void cutPoint(int fa,int u){ vis[u]=true; dfn[u]=low[u]=++cnt; int child=0; int sz=gra[u].size(); for(int i=0;i<sz;i++){ int v=gra[u][i]; if(v!=fa&&vis[v]){ low[u]=min(low[u],dfn[v]); }else if(!vis[v]){ child++; cutPoint(u,v); low[u]=min(low[u],low[v]); if((fa==-1&&child>1)||(fa!=-1&&low[v]>=dfn[u])){ cut[u]=1; } } } } int main(){ int n; while(scanf("%d",&n)==1&&n){ if(!n) break; cnt=0; for(int i=1;i<=n;i++){ gra[i].clear(); } memset(vis,false,sizeof(vis)); memset(cut,0,sizeof(cut)); int u,v; while(scanf("%d",&u)==1&&u){ while(getchar()!=' '){ scanf("%d",&v); gra[u].push_back(v); gra[v].push_back(u); } } for(int i=1;i<=n;i++){ if(!vis[i]){ cutPoint(-1,i); } } int ans=0; for(int i=1;i<=n;i++){ if(cut[i]){ ans++; } } printf("%d ",ans); } return 0; }