Given the root of a binary tree, return the maximum average value of a subtree of that tree. Answers within 10-5 of the actual answer will be accepted.
A subtree of a tree is any node of that tree plus all its descendants.
The average value of a tree is the sum of its values, divided by the number of nodes.
Example 1:
Input: root = [5,6,1]
Output: 6.00000
Explanation:
For the node with value = 5 we have an average of (5 + 6 + 1) / 3 = 4.
For the node with value = 6 we have an average of 6 / 1 = 6.
For the node with value = 1 we have an average of 1 / 1 = 1.
So the answer is 6 which is the maximum.
Example 2:
Input: root = [0,null,1] Output: 1.00000
还是dc的模板，但是
是从这里递归出去的，所以可以用+1来计算子节点的数量
int number = left + right + 1;
https://leetcode.com/problems/maximum-average-subtree/discuss/715694/Java-0ms-simple
class Solution {
private double average = 0;
public double maximumAverageSubtree(TreeNode root) {
helper(root);
return average;
}
private int helper(TreeNode root){
if(root == null)
return 0;
int left = helper(root.left);
int right = helper(root.right);
int number = left + right + 1;
if(left != 0)
root.val += root.left.val;
if(right != 0)
root.val += root.right.val;
average = Math.max(average, (double)(root.val) / number);
return number;
}
}