python列表和if语句的简单结合

将列表所有元素打印出来

cars = ['toyota', 'honda', 'mazda', 'nissan', 'mitsubishi', 'subaru', 'suzuki', 'isuzu']
for car in cars:
    new_car = car.title()
    print("Japan automobile brand: %s" % new_car)
print("
Above is Japan automobile brand !")

输出

Japan automobile brand: Toyota
Japan automobile brand: Honda
Japan automobile brand: Mazda
Japan automobile brand: Nissan
Japan automobile brand: Mitsubishi
Japan automobile brand: Subaru
Japan automobile brand: Suzuki
Japan automobile brand: Isuzu

Above is Japan automobile brand !

对列表元素进行判断

japan_cars = ['toyota', 'honda', 'mazda', 'nissan', 'mitsubishi', 'subaru', 'suzuki', 'isuzu', 'bmc']
germany_cars = 'bmc'
for car in japan_cars:
    if car != germany_cars:
        print("Japan automobile brand: " + car.title())
    else:
        print("Germany automobile brand: " + germany_cars.title())

输出

Japan automobile brand: Toyota
Japan automobile brand: Honda
Japan automobile brand: Mazda
Japan automobile brand: Nissan
Japan automobile brand: Mitsubishi
Japan automobile brand: Subaru
Japan automobile brand: Suzuki
Japan automobile brand: Isuzu
Germany automobile brand: Bmc

 测试列表是否为空

为空

cars = []
if cars:
    print("List has tuples.")
else:
    print("List in null.")

 输出

List in null.

不为空

cars = ['toyota']
if cars:
    print("List has tuples.")
else:
    print("List in null.")

输出

List has tuples.

 多个列表间进行处理

查询汽车代理商是否代理了指定品牌的汽车

agency_brands = ['toyota', 'honda', 'nissan', 'mitsubishi', 'subaru', 'suzuki', 'isuzu', 'bmc', 'audi', 'vw']
query_brands = ['ford', 'audi', 'mazda']

for query_brand in query_brands:
    if query_brand in agency_brands:
        print("Automobile brand " + query_brand + " in agency contents.")
    else:
        print("We have no " + query_brand + ".")

 输出

We have no ford.
Automobile brand audi in agency contents.
We have no mazda.