练习一百例之4--日期计算

问题及答案实例四，关于日期的简单练习
Python练习题问题如下：
简述：要求输入某年某月某日
提问：求判断输入日期是当年中的第几天？
###如果用time模块的话，将会更简单！！！

#!/usr/bin/python

# -*- coding: UTF-8 -*-
  
year = int(raw_input('year:
'))
month = int(raw_input('month:
'))
day = int(raw_input('day:
'))
  
months = (0,31,59,90,120,151,181,212,243,273,304,334)
if 0 < month <= 12:
    sum = months[month - 1]
else:
    print 'data error'
sum += day
 
leap = 0 #www.iplaypy.com
 
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
    leap = 1
if (leap == 1) and (month > 2):
    sum += 1
print 'it is the %dth day.' % sum

上面是参考答案，以下我的练习，加了一些格式校验，当然写成类可能更好看

此题，实验出来range（0）后 面不执行，不会抛出异常

#!/usr/bin/env python
#coding:utf8
import time,datetime
import os

days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
def ReadDate():
    print "Please input a date string like 20170102 or 2017-01-02"
    Dateis = raw_input("Date is:")
    Dateis = Dateis.replace('-','')  #加工成20170102
    print Dateis
    return Dateis

def Datesplite(Dateis):  #返回年月日列表
    print Dateis
    if len(Dateis) != 8:
        print 'Wrong input!'
    else:
        try:
            Year = int(Dateis[0:4])
            Moon = int(Dateis[4:6].lstrip('0'))
            Day = int(Dateis[6:8].lstrip('0'))
        except:
            print "Format is Wrong!"
        return [Year,Moon,Day]

def Datecount(list_in):
    print list_in
    cday = 0
    if list_in[0] %4 == 0 and list_in[1] > 2:
        days[1] =days[1]+1
    for i in range(list_in[1]-1):  #当range（0）时，这个后面不执行
        print days[i]
        cday += days[i]
    cday +=list_in[2]
    print cday,'th'

''' 一般调用顺序
inputdate = ReadDate()
splipdate = Datesplite(inputdate)
Datecount(splipdate)
'''

Datecount(Datesplite(ReadDate()))

使用time模块

import time
str = raw_input("输入日期")#str = "20170102"
try:
    struct_time = time.strptime(str,"%Y%m%d")
    print struct_time.tm_yday
except:
    print "wrong input,like 20170101"

这就说明，如果了解模块更多，问题更简单