DESCRIPTION:大意是给你两个字符串。编辑距离只有add和delete会产生。所以。编辑距离最短一定是两个字符串的长度差。然后...呵呵呵呵.... 猜题意就可以了...但是...我觉得这个题很不专业...题面上给的是删除时不输出字符...raner...还是要输出...还有就是...如果恰好当前对应的两个位置刚好相同..还是要modify...逗我玩呢....
总而言之。。已无力吐槽...
附代码：
#include<stdio.h>
#include<string.h>
#include<iostream>
using namespace std;
char s1[10010], s2[10010];
int main()
{
while (scanf("%s%s", s1, s2) != EOF)
{
int len1 = strlen(s1);
int len2 = strlen(s2);
if (len1 < len2)
{
for (int i=0; i<len2 - len1; ++i)
{
cout << "a " << s2[i] << endl;
}
for (int i=len2-len1; i<len2; ++i)
{
cout << "m " << s2[i] << endl;
}
}
else if (len1 == len2)
{
for (int i=0; i<len2; ++i)
{
cout << "m " << s2[i] << endl;
}
}
else if (len1 > len2)
{
// for (int i=0; i<len1-len2; ++i)
for (int i=len1-len)
{
cout << "d " << s1[i] << endl;
}
for (int i=0; i<len2; ++i)
{
cout << "m " << s2[i] << endl;
}
}
}
return 0;
}