思路:找到1-100间的特殊区间,使用if语句判断输入的数字是否在这个区间,如果在就减去这个区间最小值给这个数字(比如区间1-3,如果输入3,则3-1=2,把2给需下一次判断的值)然后循环再判断,直到这个值为0。
下边是我写的代码,欢迎各位朋友指点。
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#include <stdio.h>
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int main()
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{
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int digit = 1;
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int roman;
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while ( digit <= 100 )
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{
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printf( "%d\t", digit );
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roman = digit;
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while ( roman > 0 )
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{
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if ( roman == 100 )
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{
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printf( "C" );
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roman -= 100;
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}
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else if ( roman < 100 && roman >= 90 )
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{
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printf( "XC" );
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roman -= 90;
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}
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else if ( roman < 90 && roman >= 50 )
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{
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printf( "L" );
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roman -= 50;
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}
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else if ( roman < 50 && roman >= 49 )
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{
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printf( "IL" );
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roman -= 49;
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}
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else if ( roman < 49 && roman >= 40 )
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{
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printf( "XL" );
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roman -= 40;
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}
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else if ( roman < 40 && roman >= 10 )
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{
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printf( "X" );
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roman -= 10;
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}
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else if ( roman < 10 && roman >= 9 )
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{
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printf( "IX" );
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roman -= 9;
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}
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else if ( roman < 9 && roman >= 5 )
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{
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printf( "V" );
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roman -= 5;
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}
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else if ( roman < 5 && roman >= 4 )
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{
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printf( "IV" );
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roman -= 4;
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}
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else if ( roman < 4 && roman >= 1 )
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{
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printf( "I" );
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roman -= 1;
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}
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else
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printf( "must between 1~100 !" );
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}
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printf( "\n" );
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digit++;
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}
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return 0;
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}
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