• 第六周作业


    1.定义长度位5的整型数组,输入他们的值,用冒泡排序后输出

    public static void main(String[] args) {
            int[] a = new int[5];
            int i, j;
            int temp;
            Scanner input = new Scanner(System.in);
            System.out.println("请输入5个整数:");
            for (i = 0; i < 5; i++) {
                a[i] = input.nextInt();
            }
            for (i = 0; i < a.length - 1; i++) {
                for (j = 0; j < a.length - 1 - i; j++) {
                    if (a[j] > a[j + 1]) {
                        temp = a[j];
                        a[j] = a[j + 1];
                        a[j + 1] = temp;
                    }
                }
            }
            System.out.println("冒泡排序结果为:");
            for (i = 0; i < a.length; i++) {
                System.out.println(a[i] + "	");
            }
        }
    }

     2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"

    public static void main(String[] args) {
                Scanner sc=new Scanner(System.in);
                int[] x={34,22,35,67,45,66,12,33};
                System.out.println("请输入一个数:");
                int a=sc.nextInt();
                for(int i=0;i<x.length;i++){
                    if(x[i]==a){
                        System.out.println("下标为"+i);
                    }else{
                        System.out.println("not found");
                    }break;
                }
            }
        }


     3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。

    public static void main(String[] args) {
                Scanner sc = new Scanner(System.in);
                int[][] a = new int[5][4];
                for (int i = 0; i < 5; i++) {
                    for (int j = 0; j < 4; j++) {
                        a[i][j] = sc.nextInt();
                    }
                }
                System.out.println("输入的数组为:");
                for (int i = 0; i < 5; i++) {
                    for (int j = 0; j < 4; j++) {
                        System.out.print(a[i][j]);
                    }
                    System.out.println();
                }
          }
    }

    4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.

    public static void main(String[] args) {
                Scanner input = new Scanner(System.in);
                int[][] a = new int[5][4];
                int m = 0;
                int max=0;
                for (int i = 0; i < 3; i++) {
                    for (int j = 0; j < 4; j++) {
                        a[i][j] = m;
                        m++;
                    }
                }
                for (int i = 0; i < a.length; i++) {
                    for (int j = 0; j < a[i].length-1; j++) {
                        if(max<a[i][j]){
                            max=a[i][j];                   
                        }
                    }
                }
                System.out.println("最大值是:"+max);
              
            }
            }

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  • 原文地址:https://www.cnblogs.com/iM59/p/12696441.html
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