不多介绍了,千篇一律的正则匹配.....
import requests import re head = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/43.0.2357.130 Safari/537.36'} key = 'jcrcw.com' # 这里填主域名 lst = [] match = 'style="text-decoration:none;">(.*?)</b>' for i in range(1, 20): # 1-19页 url = "https://www.baidu.com/s?wd=inurl:{}&pn={}&oq={}&ie=utf-8".format(key, i, key) print(url) # response = requests.get(url,headers=head,cookies = cook).content response = requests.get(url, headers=head).content subdomains = re.findall(match, response.decode()) for j in subdomains: j = j.replace('<b>', '') if key in j: if j not in lst: lst.append(j) # print(lst) print(lst)
运行结果: