题目:
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
代码:
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { if(l1==null) return l2; if(l2==null) return l1; if(l1==null&&l2==null) return null; ListNode node = new ListNode(0) ; ListNode head = node; int carry = 0; while(l1!=null&&l2!=null) { int res = l1.val+l2.val+carry; node.next = new ListNode(res % 10); carry = res/10; l1 = l1.next; l2 = l2.next; node = node.next; } while(l1!=null){ int res = l1.val+carry; node.next = new ListNode(res % 10); carry = res/10; l1 = l1.next; node = node.next; } while(l2!=null){ int res = l2.val+carry; node.next = new ListNode(res % 10); carry = res/10; l2 = l2.next; node = node.next; } if(carry!=0){ node.next = new ListNode(carry); } return head.next; } }