Length of Last Word
Given a string s consists of upper/lower-case alphabets and empty space characters
' '
, return the length of last word in the string.If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s ="Hello World"
,
return5
.
算法思路:
这道题貌似是leetcode中最easy的一道了吧,心情不好,状态不佳,就找软柿子捏吧(注意字符串以空格结尾)
代码如下:
1 public class Solution { 2 public int lengthOfLastWord(String s) { 3 int length = 0; 4 for(int i = s.length() - 1; i >= 0; i--){ 5 if(s.charAt(i) != ' '){ 6 while(i >= 0 && s.charAt(i) != ' '){ 7 length++; 8 i--; 9 } 10 return length; 11 } 12 } 13 return 0; 14 } 15 }