Restore IP Addresses
Given a string containing only digits, restore it by returning all possible valid IP address combinations.
For example:
Given "25525511135"
,
return ["255.255.11.135", "255.255.111.35"]
. (Order does not matter)
算法思路:
一般而言,求出所有**,全部**,都是用穷尽法,DFS即其中一种搜索方法,相比BFS而言,代码简洁,可读性强
1 public class Solution { 2 public List<String> restoreIpAddresses(String s) { 3 List<String> result = new ArrayList<String>(); 4 if(s == null || s.length() < 4) return result; 5 dfs(result,new StringBuilder(),s,0); 6 return result; 7 } 8 9 private void dfs(List<String> result,StringBuilder pre,String suffix,int n){ 10 if(n > 3 || (n == 3 && ( suffix.length() == 0 || suffix.length() > 3 || Integer.valueOf(suffix) > 255 || (suffix.length() > 1 && suffix.charAt(0) == '0'))))return; 11 if(n == 3 && suffix.length() <= 3){ 12 result.add(pre + suffix); 13 return; 14 } 15 for(int i = 0; i < Math.min(3, suffix.length()); i++){ 16 StringBuilder oldPre = new StringBuilder(pre); 17 String tem = suffix.substring(0, i + 1); 18 int tem2Int = Integer.valueOf(tem); 19 if(tem2Int > 255 || (tem.length() > 1 && tem2Int < 10)) return; 20 pre = pre.append(tem).append('.'); 21 n++; 22 dfs(result, pre, suffix.substring(i + 1), n); 23 pre = oldPre; 24 n--; 25 } 26 } 27 }