1.Json字符串嵌套格式解析
string jsonText = "{"beijing":{"zone":"海淀","zone_en":"haidian"}}"; JObject jo = (JObject)JsonConvert.DeserializeObject(jsonText); string zone = jo["beijing"]["zone"].ToString(); string zone_en = jo["beijing"]["zone_en"].ToString();
2.Json字符串数组格式解析
string jsonArrayText = "[{'a':'a1','b':'b1'},{'a':'a2','b':'b2'}]"; //"[{'a':'a1','b':'b1'}]即使只有一个元素,也需要加上[] string jsonArrayText = "[{"a":"a1","b":"b1"},{"a":"a2","b":"b2"}]"; //上面写法和此写法效果一样 JArray jArray = (JArray)JsonConvert.DeserializeObject(jsonArrayText);//jsonArrayText必须是带[]数组格式字符串 string str = jArray[0]["a"].ToString();