构造函数按一下顺序被调用:
1.按虚拟基类被继承的顺序
2.按非虚拟基类被继承的顺序
3.按成员函数被声明的顺序
4.类自己的构造函数
#include<stdio.h> #include<iostream> #include<assert.h> using namespace std; class OBJ1 { public: OBJ1(){ cout<<"OBJ1"<<endl; } }; class OBJ2 { public: OBJ2(){ cout<<"OBJ2"<<endl; } }; class Base1 { public: Base1(){ cout<<"Base1"<<endl; } }; class Base2:public Base1 { public: Base2(){ cout<<"Base2"<<endl; } }; class Base3 { public: Base3(){ cout<<"Base3"<<endl; } }; class Base4:public Base3,public Base1 { public: Base4(){ cout<<"Base4"<<endl; } }; class Test:public Base1,public virtual Base2,public virtual Base3,public Base4 { public: Test():Base4(),Base3(),Base2(),Base1(),obj2(),obj1() { cout<<"Test"<<endl; } private: OBJ2 obj2; OBJ1 obj1; }; int main() { Test t; }