问了好多人,都不知道group_concat这个函数。
这个函数好啊,能将相同的行组合起来,省老事了。
MySQL中group_concat函数
完整的语法如下:
group_concat([DISTINCT] 要连接的字段 [Order BY ASC/DESC 排序字段] [Separator '分隔符'])
基本查询
select * from aa;
+------+------+
| id| name |
+------+------+
|1 | 10|
|1 | 20|
|1 | 20|
|2 | 20|
|3 | 200 |
|3 | 500 |
+------+------+
6 rows in set (0.00 sec)
以id分组,把name字段的值打印在一行,逗号分隔(默认)
select id,group_concat(name) from aa group by id;
+------+--------------------+
| id| group_concat(name) |
+------+--------------------+
|1 | 10,20,20|
|2 | 20 |
|3 | 200,500|
+------+--------------------+
3 rows in set (0.00 sec)
以id分组,把name字段的值打印在一行,分号分隔
select id,group_concat(name separator ';') from aa group by id;
+------+----------------------------------+
| id| group_concat(name separator ';') |
+------+----------------------------------+
|1 | 10;20;20 |
|2 | 20|
|3 | 200;500 |
+------+----------------------------------+
3 rows in set (0.00 sec)
以id分组,把去冗余的name字段的值打印在一行,
逗号分隔
select id,group_concat(distinct name) from aa group by id;
+------+-----------------------------+
| id| group_concat(distinct name) |
+------+-----------------------------+
|1 | 10,20|
|2 | 20 |
|3 | 200,500 |
+------+-----------------------------+
3 rows in set (0.00 sec)
以id分组,把name字段的值打印在一行,逗号分隔,以name排倒序
select id,group_concat(name order by name desc) from aa group by id;
+------+---------------------------------------+
| id| group_concat(name order by name desc) |
+------+---------------------------------------+
|1 | 20,20,10 |
|2 | 20|
|3 | 500,200|
+------+---------------------------------------+
3 rows in set (0.00 sec)
测试sql,项目中用到的。
SELECT EMPLOYEES.EMPID ,EMPLOYEES.EMPNAME ,DEPARTMENTS.DEPARTMENTNAME ,EMPLOYEES.DEPTID ,EMPLOYEES.EMPPWD ,EMPLOYEES.INSIDEEMAIL ,EMPLOYEES.OUTSIDEEMAIL ,EMPLOYEES.DELEFLAG ,EMPLOYEES.EMPCLASS ,(CONCAT('[', <span style="color: #ff0000;">GROUP_CONCAT</span> (ROLE.Role_Name SEPARATOR '],['), ']')) AS ROLENAME ,(concat( '[', ( SELECT <span style="color: #ff0000;">GROUP_CONCAT</span> (DEPARTMENTS.DEPARTMENTNAME separator '],[') FROM EMP_ROLE_DEPT LEFT JOIN DEPARTMENTS ON ( DEPARTMENTS.DEPARTMENTID = EMP_ROLE_DEPT.DEPTID AND DEPARTMENTS.DELEFLAG = 0 ) GROUP BY EMP_ROLE_DEPT.EMPID HAVING EMP_ROLE_DEPT.EMPID = EMPLOYEES.EMPID ),']')) AS DEPARTMENTRIGHT FROM EMPLOYEES LEFT JOIN DEPARTMENTS ON ( DEPARTMENTS.DEPARTMENTID = EMPLOYEES.DEPTID AND DEPARTMENTS.DELEFLAG = 0 ) LEFT JOIN ROLE_EMP ON (ROLE_EMP.EMP_ID = EMPLOYEES.EMPID) LEFT JOIN ROLE ON (ROLE_EMP.ROLE_ID = ROLE.ROLE_ID) <span style="color: #ff0000;"> GROUP BY EMPLOYEES.EMPID</span> HAVING EMPLOYEES.EMPID LIKE '%%' AND EMPLOYEES.EMPNAME LIKE '%%' AND EMPLOYEES.DELEFLAG = 0 AND ( EMPLOYEES.EMPCLASS = '1' OR EMPLOYEES.EMPCLASS = '2' ) AND EMPLOYEES.DEPTID = '001' LIMIT 0 ,16