u Calculate e
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 39381 Accepted Submission(s): 17893
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
cout<<"n "<<"e"<<endl;
cout<<"- -----------"<<endl;
double e[10]={0};
e[0]=1;
cout<<0<<" "<<fixed<<setprecision(0)<<e[0]<<endl;
for(int i=1;i<10;i++)
{
double temp=1.0*i;
for(int j=i-1;j>0;j--)
{
temp*=j;
}
e[i]=e[i-1]+1/temp;
if(i==1)
{
cout<<i<<" "<<fixed<<setprecision(0)<<e[i]<<endl;
}
else if(i==2)
{
cout<<i<<" "<<fixed<<setprecision(1)<<e[i]<<endl;
}
else
{
cout<<i<<" "<<fixed<<setprecision(9)<<e[i]<<endl;
}
}
return 0;
}