• POJ 2245 Lotto


          Lotto
     

    Description

    In the German Lotto you have to select 6 numbers from the set {1,2,...,49}. A popular strategy to play Lotto - although it doesn't increase your chance of winning - is to select a subset S containing k (k > 6) of these 49 numbers, and then play several games with choosing numbers only from S. For example, for k=8 and S = {1,2,3,5,8,13,21,34} there are 28 possible games: [1,2,3,5,8,13], [1,2,3,5,8,21], [1,2,3,5,8,34], [1,2,3,5,13,21], ... [3,5,8,13,21,34].

    Your job is to write a program that reads in the number k and the set S and then prints all possible games choosing numbers only from S.

    Input

    The input will contain one or more test cases. Each test case consists of one line containing several integers separated from each other by spaces. The first integer on the line will be the number k (6 < k < 13). Then k integers, specifying the set S, will follow in ascending order. Input will be terminated by a value of zero (0) for k.

    Output

    For each test case, print all possible games, each game on one line. The numbers of each game have to be sorted in ascending order and separated from each other by exactly one space. The games themselves have to be sorted lexicographically, that means sorted by the lowest number first, then by the second lowest and so on, as demonstrated in the sample output below. The test cases have to be separated from each other by exactly one blank line. Do not put a blank line after the last test case.

    Sample Input

    7 1 2 3 4 5 6 7
    8 1 2 3 5 8 13 21 34
    0
    

    Sample Output

    1 2 3 4 5 6
    1 2 3 4 5 7
    1 2 3 4 6 7
    1 2 3 5 6 7
    1 2 4 5 6 7
    1 3 4 5 6 7
    2 3 4 5 6 7
    
    1 2 3 5 8 13
    1 2 3 5 8 21
    1 2 3 5 8 34
    1 2 3 5 13 21
    1 2 3 5 13 34
    1 2 3 5 21 34
    1 2 3 8 13 21
    1 2 3 8 13 34
    1 2 3 8 21 34
    1 2 3 13 21 34
    1 2 5 8 13 21
    1 2 5 8 13 34
    1 2 5 8 21 34
    1 2 5 13 21 34
    1 2 8 13 21 34
    1 3 5 8 13 21
    1 3 5 8 13 34
    1 3 5 8 21 34
    1 3 5 13 21 34
    1 3 8 13 21 34
    1 5 8 13 21 34
    2 3 5 8 13 21
    2 3 5 8 13 34
    2 3 5 8 21 34
    2 3 5 13 21 34
    2 3 8 13 21 34
    2 5 8 13 21 34
    3 5 8 13 21 34

     1 #include<cstdio>
     2 #include<cstring>
     3 using namespace std;
     4 
     5 int n,a[15],b[15],used[15];
     6 
     7 void dfs(int cur,int num)
     8 {
     9     int i,j;
    10     if(cur==num)
    11     {
    12         for(j=0;j<num-1;j++)
    13         printf("%d ",b[j]);
    14         printf("%d
    ",b[j]);
    15         return;
    16     }
    17     for(i=0;i<n;i++)
    18     {
    19         if(!used[i]&&a[i]>b[cur-1])
    20         {
    21             b[cur]=a[i];
    22             used[i]=1;
    23             dfs(cur+1,num);
    24             used[i]=0;
    25         }
    26     }
    27 }
    28 
    29 int main()
    30 {
    31     bool flag;
    32     flag=false;
    33     while(scanf("%d",&n)&&n)
    34     {
    35         if(flag)
    36         printf("
    ");
    37         memset(used,0,sizeof(used));
    38         for(int i=0;i<n;i++)
    39         scanf("%d",&a[i]);
    40         dfs(0,6);
    41         flag=true;
    42     }
    43     return 0;
    44 }
  • 相关阅读:
    【BZOJ1000】A+B Problem ★BZOJ1000题达成★
    【BZOJ4548】小奇的糖果 set(链表)+树状数组
    【BZOJ3661】Hungry Rabbit 贪心
    Python面试题之回调函数
    Django学习笔记之CBV和FBV
    RESTful源码笔记之RESTful Framework的基本组件
    SQL学习笔记之B+树
    SQL学习笔记之MySQL索引知识点
    SQL学习笔记之B+树的几点总结
    Python面试题之Python中type和object的关系
  • 原文地址:https://www.cnblogs.com/homura/p/4703513.html
Copyright © 2020-2023  润新知