测试所用图如下：
#include<stdio.h>
#include<iostream>
#include<string.h>
#include<string>
#include<cmath>
#include<vector>
#include<set>
#define OK 1
#define ERROR 0
using namespace std;
typedef struct NODE{
int adjvex;
int weight;
NODE *next;
}node;
typedef struct {
int in;
int data;
NODE *first;
}nodeList;
typedef struct {
int num_vex;
int num_edge;
nodeList headvex[100];
}Graph;
void create(Graph *g){
scanf("%d%d",&g->num_vex,&g->num_edge);
int i,j,x,y,z;
for(i=0;i<g->num_vex;i++)
{scanf("%d",&g->headvex[i].data);
g->headvex[i].in=0;
g->headvex[i].first=NULL;
}
//相比普通邻接表，拓扑排序的邻接表只是在每个表头节点多加了一个表示入度的值(即是in)
node *e;
for(i=0;i<g->num_edge;i++){
scanf("%d%d%d",&x,&y,&z);
e=new NODE();
e->weight=z;
e->adjvex=y;
g->headvex[y].in++;
e->next=g->headvex[x].first;
g->headvex[x].first=e;
}
}
int TopologicalSort(Graph *g){
NODE *e;
int i,j,k,gettop;
int mystack[100];
int top=0;
int Count=0;
//top mystack gettop 用来模拟栈
for(i=0;i<g->num_vex;i++)
{
if(g->headvex[i].in==0)
mystack[++top]=i;//遍历邻接表表头节点，将入度为零的结点首先入栈
}
while(top!=0){//如果栈不为空，while循环继续
gettop=mystack[top--];//出栈
printf("%d ",g->headvex[gettop].data);
Count++;
for(e=g->headvex[gettop].first;e;e=e->next)
{
g->headvex[e->adjvex].in--;//删去被出栈节点所连的边，即是把与此节点邻接的点的入度减一
if(g->headvex[e->adjvex].in==0)mystack[++top]=e->adjvex;//把入度为0的点入栈
}
}
printf("
");
if(Count<g->num_vex)//如果count小于总结点数，说明不是aov网图
return ERROR;
else return OK;
}
int main(){
int i,j,k;
Graph G;
create(&G);
k=TopologicalSort(&G);
printf("ans:%d
",k);
return 0;
}
/*
14 20
0 1 2 3 4 5 6 7 8 9 10 11 12 13
0 4 1
0 5 1
0 11 1
1 4 1
1 8 1
1 2 1
2 5 1
2 6 1
2 9 1
3 2 1
3 13 1
4 7 1
5 8 1
5 12 1
6 5 1
8 7 1
9 10 1
9 11 1
10 13 1
12 9 1
*/
测试图转换成邻接表如下：
