• 记录 Ext 日历月份选择控件bug解决过程结果


    背景

    项目使用 Ext.NET 2.2.0.40838 , 对应 Ext JS4.2 版本。 结果 2017/3/31 号的时候偶然间点日历选择控件选择2月,10月等月份突然就跳到3月份,9月份之类。 就是无法选择, 选择谷歌以后发现有同样的问题, 然后各种尝试, 重写了默认属性,如下代码后解决。 收获就是调用平台有时候要知道原因才能找到未知原因并修复. 宝贵的额是Ext框架问题解决思路吧.

    现记录。 改动的部分就是 dt.setDate(1); 这一句, 设置为当前月份第一天。

    Paste_Image.png

    代码

    • 原则上放到公共js里面, 然后就行了, 确保生效。 当然也可以放在页面里面调试, 先看看是不是可行。 本项目验证通过。
    //修复日期月份模式下在本地日期为31号时跳到下个月的问题 2017年3月31日
    
    (function () { 
    
    if(!window.Ext){return;}
    if(!window.Ext.Date){return;}
    
    Ext.Date.createParser = function (format) {
        var utilDate = Ext.Date;
    
    
    
        var xf = function (format) {
            var args = Array.prototype.slice.call(arguments, 1);
    
    
            var numberTokenRe = /{(d+)}/g;
    
            return format.replace(numberTokenRe, function (m, i) {
                return args[i];
            });
        }
    
    
        var code = [
        // date calculations (note: the code below creates a dependency on Ext.Number.from())
            "var me = this, dt, y, m, d, h, i, s, ms, o, O, z, zz, u, v, W, year, jan4, week1monday,",
                "def = me.defaults,",
                "from = Ext.Number.from,",
                "results = String(input).match(me.parseRegexes[{0}]);", // either null, or an array of matched strings
    
            "if(results){",
                "{1}",
    
                "if(u != null){", // i.e. unix time is defined
                    "v = new Date(u * 1000);", // give top priority to UNIX time
                "}else{",
        // create Date object representing midnight of the current day;
        // this will provide us with our date defaults
        // (note: clearTime() handles Daylight Saving Time automatically)
                    "dt = me.clearTime(new Date);dt.setDate(1);",
    
                    "y = from(y, from(def.y, dt.getFullYear()));",
                    "m = from(m, from(def.m - 1, dt.getMonth()));",
                    "d = from(d, from(def.d, dt.getDate()));",
    
                    "h  = from(h, from(def.h, dt.getHours()));",
                    "i  = from(i, from(def.i, dt.getMinutes()));",
                    "s  = from(s, from(def.s, dt.getSeconds()));",
                    "ms = from(ms, from(def.ms, dt.getMilliseconds()));",
    
                    "if(z >= 0 && y >= 0){",
        // both the year and zero-based day of year are defined and >= 0.
        // these 2 values alone provide sufficient info to create a full date object
    
        // create Date object representing January 1st for the given year
        // handle years < 100 appropriately
                        "v = me.add(new Date(y < 100 ? 100 : y, 0, 1, h, i, s, ms), me.YEAR, y < 100 ? y - 100 : 0);",
    
        // then add day of year, checking for Date "rollover" if necessary
                        "v = !strict? v : (strict === true && (z <= 364 || (me.isLeapYear(v) && z <= 365))? me.add(v, me.DAY, z) : null);",
                    "}else if(strict === true && !me.isValid(y, m + 1, d, h, i, s, ms)){", // check for Date "rollover"
                        "v = null;", // invalid date, so return null
                    "}else{",
                        "if (W) {", // support ISO-8601
        // http://en.wikipedia.org/wiki/ISO_week_date
        //
        // Mutually equivalent definitions for week 01 are:
        // a. the week starting with the Monday which is nearest in time to 1 January
        // b. the week with 4 January in it
        // ... there are many others ...
        //
        // We'll use letter b above to determine the first week of the year.
        //
        // So, first get a Date object for January 4th of whatever calendar year is desired.
        //
        // Then, the first Monday of the year can easily be determined by (operating on this Date):
        // 1. Getting the day of the week.
        // 2. Subtracting that by one.
        // 3. Multiplying that by 86400000 (one day in ms).
        // 4. Subtracting this number of days (in ms) from the January 4 date (represented in ms).
        // 
        // Example #1 ...
        //
        //       January 2012
        //   Su Mo Tu We Th Fr Sa
        //    1  2  3  4  5  6  7
        //    8  9 10 11 12 13 14
        //   15 16 17 18 19 20 21
        //   22 23 24 25 26 27 28
        //   29 30 31
        //
        // 1. January 4th is a Wednesday.
        // 2. Its day number is 3.
        // 3. Simply substract 2 days from Wednesday.
        // 4. The first week of the year begins on Monday, January 2. Simple!
        //
        // Example #2 ...
        //       January 1992
        //   Su Mo Tu We Th Fr Sa
        //             1  2  3  4
        //    5  6  7  8  9 10 11
        //   12 13 14 15 16 17 18
        //   19 20 21 22 23 24 25
        //   26 27 28 29 30 31
        // 
        // 1. January 4th is a Saturday.
        // 2. Its day number is 6.
        // 3. Simply subtract 5 days from Saturday.
        // 4. The first week of the year begins on Monday, December 30. Simple!
        //
        // v = Ext.Date.clearTime(new Date(week1monday.getTime() + ((W - 1) * 604800000)));
        // (This is essentially doing the same thing as above but for the week rather than the day)
                            "year = y || (new Date()).getFullYear(),",
                            "jan4 = new Date(year, 0, 4, 0, 0, 0),",
                            "week1monday = new Date(jan4.getTime() - ((jan4.getDay() - 1) * 86400000));",
                            "v = Ext.Date.clearTime(new Date(week1monday.getTime() + ((W - 1) * 604800000)));",
                        "} else {",
        // plain old Date object
        // handle years < 100 properly
                            "v = me.add(new Date(y < 100 ? 100 : y, m, d, h, i, s, ms), me.YEAR, y < 100 ? y - 100 : 0);",
                        "}",
                    "}",
                "}",
            "}",
    
            "if(v){",
        // favor UTC offset over GMT offset
                "if(zz != null){",
        // reset to UTC, then add offset
                    "v = me.add(v, me.SECOND, -v.getTimezoneOffset() * 60 - zz);",
                "}else if(o){",
        // reset to GMT, then add offset
                    "v = me.add(v, me.MINUTE, -v.getTimezoneOffset() + (sn == '+'? -1 : 1) * (hr * 60 + mn));",
                "}",
            "}",
    
            "return v;"
          ].join('
    ');
    
    
    
        var regexNum = utilDate.parseRegexes.length,
                currentGroup = 1,
                calc = [],
                regex = [],
                special = false,
                ch = "",
                i = 0,
                len = format.length,
                atEnd = [],
                obj;
    
        for (; i < len; ++i) {
            ch = format.charAt(i);
            if (!special && ch == "\") {
                special = true;
            } else if (special) {
                special = false;
                regex.push(Ext.String.escape(ch));
            } else {
                obj = utilDate.formatCodeToRegex(ch, currentGroup);
                currentGroup += obj.g;
                regex.push(obj.s);
                if (obj.g && obj.c) {
                    if (obj.calcAtEnd) {
                        atEnd.push(obj.c);
                    } else {
                        calc.push(obj.c);
                    }
                }
            }
        }
    
        calc = calc.concat(atEnd);
    
        utilDate.parseRegexes[regexNum] = new RegExp("^" + regex.join('') + "$", 'i');
        utilDate.parseFunctions[format] = Ext.functionFactory("input", "strict", xf(code, regexNum, calc.join('')));
    
    }
    })();
    
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  • 原文地址:https://www.cnblogs.com/hijushen/p/10468660.html
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