• 课程四(Convolutional Neural Networks),第四 周(Special applications: Face recognition & Neural style transfer) —— 3.Programming assignments:Face Recognition for the Happy House


    Face Recognition for the Happy House

    Welcome to the first assignment of week 4! Here you will build a face recognition system. Many of the ideas presented here are from FaceNet. In lecture, we also talked about DeepFace.

    Face recognition problems commonly fall into two categories:

    • Face Verification - "is this the claimed person?". For example, at some airports, you can pass through customs by letting a system scan your passport and then verifying that you (the person carrying the passport) are the correct person. A mobile phone that unlocks using your face is also using face verification. This is a 1:1 matching problem.
    • Face Recognition - "who is this person?". For example, the video lecture showed a face recognition video (https://www.youtube.com/watch?v=wr4rx0Spihs) of Baidu employees entering the office without needing to otherwise identify themselves. This is a 1:K matching problem.

    FaceNet learns a neural network that encodes a face image into a vector of 128 numbers. By comparing two such vectors, you can then determine if two pictures are of the same person.

    In this assignment, you will:

    • Implement the triplet loss function
    • Use a pretrained model to map face images into 128-dimensional encodings
    • Use these encodings to perform face verification and face recognition

    In this exercise, we will be using a pre-trained model which represents ConvNet activations using a "channels first" convention, as opposed to the "channels last" convention used in lecture and previous programming assignments. In other words, a batch of images will be of shape (m,nC,nH,nW) instead of (m,nH,nW,nC). Both of these conventions have a reasonable amount of traction among open-source implementations; there isn't a uniform standard yet within the deep learning community.

    【中文翻译】

    幸福之家面孔识别
    欢迎来到4第一个任务!在这里, 你将建立一个人脸识别系统。这里提出的许多想法都来自 FaceNet。在演讲中, 我们也谈到了 DeepFace。
    识别问题一般分为:
    • 人脸验证-"这是被要求的人?例如, 在一些机场, 您可以通过让系统扫描您的护照, 然后验证您 (携带护照的人) 是正确的人通过海关。用你的脸开锁的手机也使用脸部验证。这是一个1:1 匹配的问题。
    • 人脸识别-"谁是这个人?例如, 视频讲座显示了百度员工进入办公室的人脸识别视频 (https://www.youtube.com/watch?v=wr4rx0Spihs), 而不需要以其他方式识别自己。这是一个 1: K 匹配问题。
    FaceNet 是一种神经网络, 将脸部图像编码为128数字的向量。通过比较两个这样的向量, 您就可以确定两张图片是否是同一个人。
     
    在这个作业, :
    • 实现 triplet损失函数
    • 使用 pretrained 模型图像映射128编码
    • 使用这些编码执行验证识别

    在本练习中, 我们将使用一个预先训练的模型, 它使用 "通道第一" 约定, 而不是在讲课和以前的编程任务中使用的 "通道最后" 约定。换言之, 一批图像的形状是 (m,nC,nH,nW)而不是 (m,nH,nW,nC)。这公约开源实现合理;在深入学习的社区里还没有统一的标准。

    Let's load the required packages.

    【code】

    from keras.models import Sequential
    from keras.layers import Conv2D, ZeroPadding2D, Activation, Input, concatenate
    from keras.models import Model
    from keras.layers.normalization import BatchNormalization
    from keras.layers.pooling import MaxPooling2D, AveragePooling2D
    from keras.layers.merge import Concatenate
    from keras.layers.core import Lambda, Flatten, Dense
    from keras.initializers import glorot_uniform
    from keras.engine.topology import Layer
    from keras import backend as K
    K.set_image_data_format('channels_first')
    import cv2
    import os
    import numpy as np
    from numpy import genfromtxt
    import pandas as pd
    import tensorflow as tf
    from fr_utils import *
    from inception_blocks_v2 import *
    
    %matplotlib inline
    %load_ext autoreload
    %autoreload 2
    
    np.set_printoptions(threshold=np.nan)
    

    0 - Naive Face Verification

    In Face Verification, you're given two images and you have to tell if they are of the same person. The simplest way to do this is to compare the two images pixel-by-pixel. If the distance between the raw images are less than a chosen threshold, it may be the same person!

    Of course, this algorithm performs really poorly, since the pixel values change dramatically due to variations in lighting, orientation of the person's face, even minor changes in head position, and so on.

    You'll see that rather than using the raw image, you can learn an encoding f(img) so that element-wise comparisons of this encoding gives more accurate judgements as to whether two pictures are of the same person.

    【中文翻译】

    0-可爱面孔验证
    在人脸验证中, 你得到了两个图像, 你必须告诉他们是否是同一个人。最简单的方法是将两个图像逐个像素地进行比较。如果原始图像之间距离小于选定阈值, 则可能同一个人!
    图片见英文部分
    
    当然, 这个算法执行得非常差, 英文光照变化, 人的脸的方向, 甚至在头部位置的轻微变化, 等等都会引起像素值的变化。
    您将看到, 不是使用原始图像, 您可以将图片通过网络学习输出一个编码 f (img), 将此编码的元素进行比较, 可以更准确地判断两张图片是否是同一个人。

     

    1 - Encoding face images into a 128-dimensional vector

    1.1 - Using an ConvNet to compute encodings

    The FaceNet model takes a lot of data and a long time to train. So following common practice in applied deep learning settings, let's just load weights that someone else has already trained. The network architecture follows the Inception model from Szegedy et al.. We have provided an inception network implementation. You can look in the file inception_blocks.py to see how it is implemented (do so by going to "File->Open..." at the top of the Jupyter notebook).

    The key things you need to know are:

    • This network uses 96x96 dimensional RGB images as its input. Specifically, inputs a face image (or batch of m face images) as a tensor of shape (m,nC,nH,nW)=(m,3,96,96)
    • It outputs a matrix of shape (m,128) that encodes each input face image into a 128-dimensional vector

    【中文翻译】

    1-图像编码128向量
     
    1.1-使用 ConvNet 计算编码
    FaceNet 模型需要大量的数据和很长的时间来训练。因此, 在应用深层学习设置的常见实践中, 我们只需加载其他人已经训练过的权重。网络体系结构遵循了 Szegedy 等的Inception 模型。我们已经提供了一个inception 网络的实现代码。您可以在文件inception_blocks.py 中查看它是如何实现的 (通过在 Jupyter 笔记本的顶部 "File->Open...")。
     
    需要了解关键事项:
    • 该网络采用96x96 维 RGB 图像作为输入。具体地说, 输入张人脸图像 (一批 m张 人图像) 作为张量,shape为 (m,nC,nH,nW)=(m,3,96,96)
    • 输出shape为 (m, 128) , 将每个输入人脸图像编码128向量 

    Run the cell below to create the model for face images.

    【code】

    FRmodel = faceRecoModel(input_shape=(3, 96, 96))
    
    print("Total Params:", FRmodel.count_params())
    

    【result】

    Total Params: 3743280
    

    Expected Output

    Total Params: 3743280

    By using a 128-neuron fully connected layer as its last layer, the model ensures that the output is an encoding vector of size 128. You then use the encodings the compare two face images as follows:

    By computing a distance between two encodings and thresholding, you can determine if the two pictures represent the same person

    So, an encoding is a good one if:

    • The encodings of two images of the same person are quite similar to each other
    • The encodings of two images of different persons are very different

    The triplet loss function formalizes this, and tries to "push" the encodings of two images of the same person (Anchor and Positive) closer together, while "pulling" the encodings of two images of different persons (Anchor, Negative) further apart. 

    In the next part, we will call the pictures from left to right: Anchor (A), Positive (P), Negative (N)

    1.2 - The Triplet Loss

    For an image x, we denote(表示) its encoding f(x), where ff is the function computed by the neural network.

    Training will use triplets of images (A,P,N):

    • A is an "Anchor" image--a picture of a person.
    • P is a "Positive" image--a picture of the same person as the Anchor image.
    • N is a "Negative" image--a picture of a different person than the Anchor image.

    These triplets are picked from our training dataset. We will write (A(i),P(i),N(i)) to denote the i-th training example. 

     You'd like to make sure that an image A(i)of an individual is closer to the Positive P(i) than to the Negative image N(i) by at least a margin α:

     

    You would thus like to minimize the following "triplet cost":

    Here, we are using the notation "[z]+" to denote max(z,0).

    Notes:

    • The term (1) is the squared distance between the anchor "A" and the positive "P" for a given triplet; you want this to be small.
    • The term (2) is the squared distance between the anchor "A" and the negative "N" for a given triplet, you want this to be relatively large, so it thus makes sense to have a minus sign preceding it.
    • α is called the margin. It is a hyperparameter that you should pick manually. We will use α=0.2.

     Most implementations also normalize the encoding vectors to have norm equal one (i.e., f(img)2=1); you won't have to worry about that here.

    Exercise: Implement the triplet loss. Here are the 4 steps: 

    Useful functions: tf.reduce_sum()tf.square()tf.subtract()tf.add()tf.maximum(). For steps 1 and 2, you will need to sum over the entries of

     while for step 4 you will need to sum over the training examples.

    【code】
    # GRADED FUNCTION: triplet_loss
    
    def triplet_loss(y_true, y_pred, alpha = 0.2):
        """
        Implementation of the triplet loss as defined by formula (3)
        
        Arguments:
        y_true -- true labels, required when you define a loss in Keras, you don't need it in this function.
        y_pred -- python list containing three objects:
                anchor -- the encodings for the anchor images, of shape (None, 128)
                positive -- the encodings for the positive images, of shape (None, 128)
                negative -- the encodings for the negative images, of shape (None, 128)
        
        Returns:
        loss -- real number, value of the loss
        """
        
        anchor, positive, negative = y_pred[0], y_pred[1], y_pred[2]
        
        ### START CODE HERE ### (≈ 4 lines)
        # Step 1: Compute the (encoding) distance between the anchor and the positive, you will need to sum over axis=-1
        pos_dist =  tf.reduce_sum(tf.square(tf.subtract(anchor, positive)),axis=-1)
        # Step 2: Compute the (encoding) distance between the anchor and the negative, you will need to sum over axis=-1
        neg_dist =  tf.reduce_sum(tf.square(tf.subtract(anchor, negative)),axis=-1)
        # Step 3: subtract the two previous distances and add alpha.
        basic_loss = tf.add(tf.subtract(pos_dist,neg_dist),alpha)
        # Step 4: Take the maximum of basic_loss and 0.0. Sum over the training examples.
        loss = tf.reduce_sum(tf.maximum(basic_loss, 0.0))
        ### END CODE HERE ###
        
        return loss
    
    with tf.Session() as test:
        tf.set_random_seed(1)
        y_true = (None, None, None)
        y_pred = (tf.random_normal([3, 128], mean=6, stddev=0.1, seed = 1),
                  tf.random_normal([3, 128], mean=1, stddev=1, seed = 1),
                  tf.random_normal([3, 128], mean=3, stddev=4, seed = 1))
        loss = triplet_loss(y_true, y_pred)
        
        print("loss = " + str(loss.eval()))
    

    【reuslt】

    loss = 528.143
    

    Expected Output:

    loss 528.143

      

    2 - Loading the trained model

    FaceNet is trained by minimizing the triplet loss. But since training requires a lot of data and a lot of computation, we won't train it from scratch here(从头开始). Instead, we load a previously trained model. Load a model using the following cell; this might take a couple of minutes to run.

    【code】

    FRmodel.compile(optimizer = 'adam', loss = triplet_loss, metrics = ['accuracy'])
    load_weights_from_FaceNet(FRmodel)
    

    Here're some examples of distances between the encodings between three individuals:  

    3 - Applying the model

    Back to the Happy House! Residents are living blissfully since you implemented happiness recognition for the house in an earlier assignment.

    However, several issues keep coming up: The Happy House became so happy that every happy person in the neighborhood is coming to hang out in your living room. It is getting really crowded, which is having a negative impact on the residents of the house. All these random happy people are also eating all your food.

    So, you decide to change the door entry policy, and not just let random happy people enter anymore, even if they are happy! Instead, you'd like to build a Face verification system so as to only let people from a specified list come in. To get admitted, each person has to swipe an ID card (identification card) to identify themselves at the door. The face recognition system then checks that they are who they claim to be.

    3.1 - Face Verification

    Let's build a database containing one encoding vector for each person allowed to enter the happy house. To generate the encoding we use img_to_encoding(image_path, model) which basically runs the forward propagation of the model on the specified image.

    Run the following code to build the database (represented as a python dictionary). This database maps each person's name to a 128-dimensional encoding of their face.

    【code】

    database = {}
    database["danielle"] = img_to_encoding("images/danielle.png", FRmodel)
    database["younes"] = img_to_encoding("images/younes.jpg", FRmodel)
    database["tian"] = img_to_encoding("images/tian.jpg", FRmodel)
    database["andrew"] = img_to_encoding("images/andrew.jpg", FRmodel)
    database["kian"] = img_to_encoding("images/kian.jpg", FRmodel)
    database["dan"] = img_to_encoding("images/dan.jpg", FRmodel)
    database["sebastiano"] = img_to_encoding("images/sebastiano.jpg", FRmodel)
    database["bertrand"] = img_to_encoding("images/bertrand.jpg", FRmodel)
    database["kevin"] = img_to_encoding("images/kevin.jpg", FRmodel)
    database["felix"] = img_to_encoding("images/felix.jpg", FRmodel)
    database["benoit"] = img_to_encoding("images/benoit.jpg", FRmodel)
    database["arnaud"] = img_to_encoding("images/arnaud.jpg", FRmodel)
    

    Now, when someone shows up at your front door and swipes their ID card (thus giving you their name), you can look up their encoding in the database, and use it to check if the person standing at the front door matches the name on the ID. 

    【中文翻译】  

    3-应用模型
    回到Happy House! 自从你在早先的任务中实现了对进入房子的人的幸福感辨识, 居民们就生活得很快乐。
    然而, 有几个问题不断出现: 快乐的房子变得如此快乐, 以至于邻里中的每个快乐的人都来到你的起居室里闲逛。它变得非常拥挤, 这对房子的居民产生了负面影响。所有这些快乐的人也吃你所有的食物。
    所以, 决定改变的进政策, 不仅仅是快乐进入, 即使他们快乐!相反, 您希望建立一个人脸验证系统, 以便只允许来自指定列表的用户进来。为了得到允许, 每个人都在门口必须刷卡 (身份证), 以识别自己。脸部识别系统然后检查他们是否是他们自称的人。

      

    3.1 人脸验证
    让我们建立一个数据库, 其中为每个允许进入快乐屋的人准备一个编码向量,。要生成编码, 我们使用 img_to_encoding (image_path, model), 它基本上是在指定的图像上运行模型的正向传播。
    运行以下代码以生成数据库 (表示为 python 字典)。这个数据库把每个人的名字映射成给予他们面部图片的128维编码。

    【code】

    database = {}
    database["danielle"] = img_to_encoding("images/danielle.png", FRmodel)
    database["younes"] = img_to_encoding("images/younes.jpg", FRmodel)
    database["tian"] = img_to_encoding("images/tian.jpg", FRmodel)
    database["andrew"] = img_to_encoding("images/andrew.jpg", FRmodel)
    database["kian"] = img_to_encoding("images/kian.jpg", FRmodel)
    database["dan"] = img_to_encoding("images/dan.jpg", FRmodel)
    database["sebastiano"] = img_to_encoding("images/sebastiano.jpg", FRmodel)
    database["bertrand"] = img_to_encoding("images/bertrand.jpg", FRmodel)
    database["kevin"] = img_to_encoding("images/kevin.jpg", FRmodel)
    database["felix"] = img_to_encoding("images/felix.jpg", FRmodel)
    database["benoit"] = img_to_encoding("images/benoit.jpg", FRmodel)
    database["arnaud"] = img_to_encoding("images/arnaud.jpg", FRmodel)

    现在, 当有人出现在你的前门, 并刷他们的身份证 (从而给你他们的名字), 你可以在数据库中查找他们的编码, 并使用它来检查站在前门的人是否与 id 上的名称匹配。 

    Exercise: Implement the verify() function which checks if the front-door camera picture (image_path) is actually the person called "identity". You will have to go through the following steps:

    1. Compute the encoding of the image from image_path
    2. Compute the distance about this encoding and the encoding of the identity image stored in the database
    3. Open the door if the distance is less than 0.7, else do not open.

    As presented above, you should use the L2 distance (np.linalg.norm). (Note: In this implementation, compare the L2 distance, not the square of the L2 distance, to the threshold 0.7.)

    【中文翻译】

    练习: 实现verify() 函数, 检查前门相机图片 (image_path) 是否实际上是被称为 "identity" 的人。需要执行以下步骤:
    1.  image_path 中计算图像编码
    2. 计算编码与存储数据库标识图像编码的距离
    3. 如果距离小于 0.7, 则打开门, 否则不打开。
    如上所述, 您应该使用 L2 距离 (np.linalg.norm)。(注意: 在此实现中, 将 L2 距离 (而不是 L2 距离的平方) 与阈值0.7 进行比较。

    【code】

    # GRADED FUNCTION: verify
    
    def verify(image_path, identity, database, model):
        """
        Function that verifies if the person on the "image_path" image is "identity".
        
        Arguments:
        image_path -- path to an image
        identity -- string, name of the person you'd like to verify the identity. Has to be a resident of the Happy house.
                    字符串, 您要验证身份的人的姓名。必须是幸福之家的居民
        database -- python dictionary mapping names of allowed people's names (strings) to their encodings (vectors).
        model -- your Inception model instance in Keras
        
        Returns:
        dist -- distance between the image_path and the image of "identity" in the database.
        door_open -- True, if the door should open. False otherwise.
        """
        
        ### START CODE HERE ###
        
        # Step 1: Compute the encoding for the image. Use img_to_encoding() see example above. (≈ 1 line)
        encoding =  img_to_encoding(image_path,model)
        
        # Step 2: Compute distance with identity's image (≈ 1 line)
        dist = np.linalg.norm(encoding - database[identity])
        
        # Step 3: Open the door if dist < 0.7, else don't open (≈ 3 lines)
        if dist<0.7:
            print("It's " + str(identity) + ", welcome home!")
            door_open = True
        else:
            print("It's not " + str(identity) + ", please go away")
            door_open = False
            
        ### END CODE HERE ###
            
        return dist, door_open
    

    【整理者注释】

    Younes is trying to enter the Happy House and the camera takes a picture of him ("images/camera_0.jpg"). Let's run your verification algorithm on this picture:  

     

    【code】

    verify("images/camera_0.jpg", "younes", database, FRmodel)
    

    【result】

    It's younes, welcome home!
    (0.65939283, True)
    

    Expected Output:

    It's younes, welcome home! (0.65939283, True)

     

    Benoit, who broke the aquarium(水族馆) last weekend, has been banned from the house and removed from the database. He stole Kian's ID card and came back to the house to try to present himself as Kian. The front-door camera took a picture of Benoit ("images/camera_2.jpg). Let's run the verification algorithm to check if benoit can enter.  

     

    【code】

    verify("images/camera_2.jpg", "kian", database, FRmodel)
    

    【result】  

    It's not kian, please go away
    Out[11]:
    (0.86224014, False)
    

    Expected Output:

    It's not kian, please go away (0.86224014, False)

      

    3.2 - Face Recognition

    Your face verification system is mostly working well. But since Kian got his ID card stolen, when he came back to the house that evening he couldn't get in!

    To reduce such shenanigans, you'd like to change your face verification system to a face recognition system. This way, no one has to carry an ID card anymore. An authorized person can just walk up to the house, and the front door will unlock for them!

    You'll implement a face recognition system that takes as input an image, and figures out if it is one of the authorized persons (and if so, who). Unlike the previous face verification system, we will no longer get a person's name as another input.

    Exercise: Implement who_is_it(). You will have to go through the following steps:

    1. Compute the target encoding of the image from image_path
    2. Find the encoding from the database that has smallest distance with the target encoding.
      • Initialize the min_dist variable to a large enough number (100). It will help you keep track of what is the closest encoding to the input's encoding.
      • Loop over the database dictionary's names and encodings. To loop use for (name, db_enc) in database.items().
        • Compute L2 distance between the target "encoding" and the current "encoding" from the database.
        • If this distance is less than the min_dist, then set min_dist to dist, and identity to name.

    【中文翻译】

    3.2- 人识别
     
    你的脸部验证系统大多工作正常。但是,自从 Kian 的身份证被偷,那天晚上回到家里他也!
    为了减少这种恶作剧, 你把你的人脸验证系统改成人脸识别系统。这样, 没有人再携带身份证了。一个授权可以直接房子, 前门他们解开!
    你将实现一个人脸识别系统,将图像作为输入, 并指出, 它是否是一个被授的权人员 (如果是的话, 谁)。不像以前的人脸验证系统, 我们将不再将一个人的名字作为另一个输入。
    练习: 实施 who_is_it ()。需要执行以下步骤:
    1.  image_path 中计算图像目标编码
    2. 从数据库中查找与目标编码具有最小距离的编码。
         将 min_dist 变量初始化为足够大的数字 (100)。它将帮助您跟踪最接近输入编码的编码。
         循环遍历数据库字典的名称和编码。要使用循环,则使用for (name, db_enc) in database.items()
          计算目标 "编码" 与数据库中当前 "编码" 之间的 L2 距离。
          如果此距离小于 min_dist, 则将 min_dist 的值设置为 "dist", 并将name设置为identity。

    【code】

    # GRADED FUNCTION: who_is_it
    
    def who_is_it(image_path, database, model):
        """
        Implements face recognition for the happy house by finding who is the person on the image_path image.
        
        Arguments:
        image_path -- path to an image
        database -- database containing image encodings along with the name of the person on the image
        model -- your Inception model instance in Keras
        
        Returns:
        min_dist -- the minimum distance between image_path encoding and the encodings from the database
        identity -- string, the name prediction for the person on image_path
        """
        
        ### START CODE HERE ### 
        
        ## Step 1: Compute the target "encoding" for the image. Use img_to_encoding() see example above. ## (≈ 1 line)
        encoding = img_to_encoding(image_path,model)
        
        ## Step 2: Find the closest encoding ##
        
        # Initialize "min_dist" to a large value, say 100 (≈1 line)
        min_dist =100
        
        # Loop over the database dictionary's names and encodings.
        for (name, db_enc) in database.items():
            
            # Compute L2 distance between the target "encoding" and the current "emb" from the database. (≈ 1 line)
            dist =np.linalg.norm(encoding-db_enc)
    
            # If this distance is less than the min_dist, then set min_dist to dist, and identity to name. (≈ 3 lines)
            if  dist<min_dist:
                min_dist = dist
                identity = name
    
        ### END CODE HERE ###
        
        if min_dist > 0.7:
            print("Not in the database.")
        else:
            print ("it's " + str(identity) + ", the distance is " + str(min_dist))
            
        return min_dist, identity
    

    Younes is at the front-door and the camera takes a picture of him ("images/camera_0.jpg"). Let's see if your who_it_is() algorithm identifies Younes.  

    【code】

    who_is_it("images/camera_0.jpg", database, FRmodel)
    

    【result】

    it's younes, the distance is 0.659393
    (0.65939283, 'younes')

    Expected Output:

    it's younes, the distance is 0.659393 (0.65939283, 'younes')

      

    You can change "camera_0.jpg" (picture of younes) to "camera_1.jpg" (picture of bertrand) and see the result.

     

    Your Happy House is running well. It only lets in authorized persons, and people don't need to carry an ID card around anymore!

    You've now seen how a state-of-the-art face recognition system works.

    Although we won't implement it here, here're some ways to further improve the algorithm:

    • Put more images of each person (under different lighting conditions, taken on different days, etc.) into the database. Then given a new image, compare the new face to multiple pictures of the person. This would increae accuracy.
    • Crop the images to just contain the face, and less of the "border" region around the face. This preprocessing removes some of the irrelevant pixels around the face, and also makes the algorithm more robust.

    What you should remember:

    • Face verification solves an easier 1:1 matching problem; face recognition addresses a harder 1:K matching problem.
    • The triplet loss is an effective loss function for training a neural network to learn an encoding of a face image.
    • The same encoding can be used for verification and recognition. Measuring distances between two images' encodings allows you to determine whether they are pictures of the same person.
     

    Congrats on finishing this assignment!

    References:

      

      

      

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  • 原文地址:https://www.cnblogs.com/hezhiyao/p/8438857.html
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