• 【oracle/语法】With语句的写法


    Sample1:

    with temp AS (
      select * from emp where rownum<11)
    select * from temp

    Result:

    SQL> with temp AS (
      2    select * from emp where rownum<11)
      3  select * from temp;
    
            ID NAME                                            AGE     SALARY CREATE_TIME
    ---------- ---------------------------------------- ---------- ---------- ---------------------------------------------------------------------------
           561 NDRKPHCF                                         40      43533 07-9月 -21 06.32.42.000000 下午
           562 VOMTMOBLCBVKIGVOZSN                              33      23063 07-9月 -21 06.32.42.000000 下午
           563 GKDDBKTFAUON                                     63      14078 07-9月 -21 06.32.42.000000 下午
           564 MHCEIQMT                                         64      11360 07-9月 -21 06.32.42.000000 下午
           565 IVKRXCHYROE                                      28      38106 07-9月 -21 06.32.42.000000 下午
           566 GROURMS                                          25      33055 07-9月 -21 06.32.42.000000 下午
           567 BEUEKLUL                                         63      23546 07-9月 -21 06.32.42.000000 下午
           568 QIITGBC                                          41      45708 07-9月 -21 06.32.42.000000 下午
           569 OTSCIZLDWMJZFV                                   32      28990 07-9月 -21 06.32.42.000000 下午
           570 KQZFWBK                                          64      45629 07-9月 -21 06.32.42.000000 下午
    
    已选择10行。

    Sample2:

    with cityOldestWomen as (
    select id,name,gender,cityname,birthymd from (
    select 
    id,name,gender,cityname,to_char(birthday,'yyyy-MM-dd') as birthymd, 
    rank() over (partition by cityname order by birthday) as seq
    from customer
    where gender='f')
    where seq=1
    order by id)
    select * from cityOldestWomen

    Result:

    SQL> with cityOldestWomen as (
      2  select id,name,gender,cityname,birthymd from (
      3  select
      4  id,name,gender,cityname,to_char(birthday,'yyyy-MM-dd') as birthymd,
      5  rank() over (partition by cityname order by birthday) as seq
      6  from customer
      7  where gender='f')
      8  where seq=1
      9  order by id)
     10  select * from cityOldestWomen;
    
            ID NAME                                     G CITYNAME                                 BIRTHYMD
    ---------- ---------------------------------------- - ---------------------------------------- ----------
             1 XGZLORILKOGWELLJI                        f 山海关                                   1970-01-02
             2 JFMOXKKFDJPSNBNQS                        f 绥中                                     1970-01-03
             3 WKMIILRQAKY                              f 北戴河                                   1970-01-04
            23 MKSREQXPKJTWSK                           f 兴城                                     1970-01-24
            30 ILXYETNXOKXSB                            f 津滨                                     1970-01-31
    
    SQL>

    END

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  • 原文地址:https://www.cnblogs.com/heyang78/p/15368368.html
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