import datetime
t1 = datetime.datetime.strptime("2017-9-06 10:30:00", "%Y-%m-%d %H:%M:%S")
t2 = datetime.datetime.strptime("2017-9-06 12:30:00", "%Y-%m-%d %H:%M:%S")
interval_time = (t2 - t1).seconds # 输入的结果:7200 忽略微秒和天
total_interval_time = (t2 - t1).total_seconds() # 输出结果是: 7200.0
print (interval_time)
print (total_interval_time)
在python中经常会用到计算两个时间差,两个日期类型进行相减可以获取到时间差。
经常会使用seconds来获取,其实seconds获取的是仅仅是时间差的秒数,忽略微秒数,忽略天数。
total_seconds()是获取两个时间之间的总差。
import datetime
t1 = datetime.datetime.strptime("2017-9-06 10:30:00", "%Y-%m-%d %H:%M:%S")
t2 = datetime.datetime.strptime("2017-9-06 12:30:00", "%Y-%m-%d %H:%M:%S")
interval_time = (t2 - t1).seconds # 输入的结果:7200
total_interval_time = (t2 - t1).total_seconds() # 输出结果是: 7200.0
print('interval_time_01>>', interval_time)
print('total_interval_time_01>>', total_interval_time)
# 换一个方式
t1 = datetime.datetime.strptime("2017-9-06 10:30:00", "%Y-%m-%d %H:%M:%S")
t2 = datetime.datetime.strptime("2017-9-08 12:30:00", "%Y-%m-%d %H:%M:%S")
interval_time = (t2 - t1).seconds # 输入的结果:7200
total_interval_time = (t2 - t1).total_seconds() # 输出结果是: 180000.0
print('interval_time_02>>', interval_time)
print('total_interval_time_02>>', total_interval_time)
td = (t2 - t1)
print('td_01>>', (td.microseconds + (td.seconds + td.days * 24 * 3600) * 10 ** 6) / 10 ** 6)
# datetime.timedelta([days[, seconds[, microseconds[, milliseconds[, minutes[, hours[, weeks]]]]]]])
td = datetime.timedelta(6, 5, 1, 800, 12, 3)
print('td_02>>', td) # 6 days, 3:12:05.800001
print('td.seconds_01>>', td.seconds) # 11525 忽略微秒和天
print('td.total_seconds()_01>>', td.total_seconds()) # 529925.800001
输出:
interval_time_01>> 7200
total_interval_time_01>> 7200.0
interval_time_02>> 7200
total_interval_time_02>> 180000.0
td_01>> 180000.0
td_02>> 6 days, 3:12:05.800001
td.seconds_01>> 11525
td.total_seconds()_01>> 529925.800001